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ionic equilibriam
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ph=10
[H+]=10^(-10)M
[OH-]=10^(-4)M
It means in 1L sol. moles of [OH-]=10^(-4)
in .5L sol moles of [OH-]=5 X 10^(-5)
therefore,moles to be dissolved = 5 X 10^(-5)/2 = 2.5 X 10^(-5)
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1. G=H-TS
G=77.81x10^3-400x0.122x10^3
G=2.838x10^4
Now,
G=-2.303RTlogK
On solving and putting the values
K=1.97x10^-4
Plz.. rate me if correct
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