| Message |
|
|
|
no u should give at least 0 or 1
|
|
|
|
|
every nucleoph. is a base a nucleo. is a one which donates electrons to a species and if a species can donate e- to another then definitely it can dinate to H+ as well. and if a species donates e- to H+ then it is called a base so all nuc. are bases. so....if OH- donate e- to H+ then it is a base or if it donates e- to other species then it is a nucleoph.
|
|
|
|
|
it is not against aufbau principle it states that pairing up of electrons in the degenerate orbitals takes place only after each degenerate orbital has at least one electron this is only for filling up of electrons . this q has nothing to do with that principle...the q could have been while filling up we fill up 4s first then 3d bcos 4s has lower energy but while removing we don't follow this? for this the ans is after the filling of electrons 4s has higher energy than 3d so it is easy to remove an e- from a high energy orbital.....but an empty 4s has lower energy than empty 3d
|
|
|
|
- - - 9 3 9 the total no of no. is 243 now when we fix the first 2 digits the sum of the once place for the diff no. with the same tens and hundreds place is 45 now ther can be 9*3 =27 such combinations for the tens and the hundreds place so the sum of all the units place is 45*27 similarly the sum of all the tens place is (1+4+9)*10(bcos tens place)* 81 sum of all hundreds place is 45*100*27 total = 45*27+140*81+4500*27 = 1215+11340+12150 = 134055 so ans is (a)
|
|
|
|
|
2) EDIT 4 the green ones are the hydrogen bonds
|
|
|
|
|
well there is nothing much u fix the N's in the first 2 places remaining there are 10 letters they can permute in 10!/3!.3!.2! bcos there are 3 A's 3 S's and 2 I's
|
|
|
|
|
for the first 2 q plz go through ur XII class text and for the next q the ans is pentan-2-one. water should be removed immediately bcos it reacts with the ester formed to give an acid and alcohol.....or u can say that the reaction is reversible so by lechatlier's principle if we remove one of the product that is water the reaction is pushed in the forward dir.
|
|
|
|
|
....what is density, mass per unit volume....in moist air u have water molecules in air so,per unit volume u have more mass in moist air than in dry air. so it has more density than dry air
|
|
|
|
|
hmmmmmm............well......of course i know that the program can be written in a much more efficient way ....i was trying to give the simplest of code so that he could understand it.....there is a more efficient way check this out
for(i=0;i<n;i++)
for(j=i;j<n;j++)
cout<<a[i][j];
|
|
|
|
|
sir...i think the q is it is stable when it is on a ride...i think he is asking why is easy to balance while riding but not when stationary.....that is due to the gyroscopic effect....
|
|
|
|
|
....sorry i meant file object.....is the problem something like this u modify a record then it asks u what to do then u say display ...now it does not display but again asks u what to do now again u say display it displays....
|
|
|
|
|
from the q we can infer that there will be nC2 points and of these u select 2 points so the ans is (nC2)C2
|
|
|
|
|
ok.....then check for this ......try creating another file pointer just before the display while loop and use that newly created pointer in the while loop.....just try it..
|
|
|
|
|
wait ......i posted a proper full code ......but what is seen is not proper.....
|
|
|
|
|
yes u can make a separate file for that and include it along with ur header files this is within the scope of class XII
|
|
|
|