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i got around 265, can i know which college and which streams would be available.

sure, helldriver.
ull make it jee but with a rank of about 2500+. bhu is a great option.

Morrison and Boyd is good for understanding, but Arihant Organic is the perfect book for JEE

As no one is interested in this question, i am telling the answer.
when heat is supplied to the spheres, each expand in equal proportion, but as A expands, its centre of mass rises, and hence some of the energy is used in increasing the potential energy. B cannot change its potential energy, therefore its temperature would be higher than A.
aditya_arora04 was thinkng in the right direction.

please rate the answer

I am not going to tell anything till someone gets the right answer, or if it goes on for too long.

A sphere A is placed on a smooth table. Another sphere B is suspended from a string which is attached to its centre. Both are identical in all respects. equal quantity of heat is supplied to both. all kind of heat losses are neglected and the string is perfectly insulating and does not expand or contract on heating. the string's diameter is negligible. if T_aand T_bare the final temperatures of A and B, then

a)T_a<T_b

b) T_a >T_b

c) T_a=T_b

d) none of these

Tell me the answer, with the working. most probably someone would get the answer, so i may not have to tell you the working. i will let u know if someone is right.

But a strictly function's slope never does become zero. this function is called a non-decreasing function. here the word STRICTLY is being used, therefore the slope has to be always greater than zero. check out any maths book, there this is specified. i checked in arihant maths. if they had not specified strictly, it would had been right.

and as we move towards the right of 0, the value of the function is constant for a short time, similarly as we move left.{(0-h,0+h) h

0}. therefore it does not increase with the increase of the value of x for atleast a short interval, which cannot be overlooked.

The graph is like a S shaped curve, similar to y=x³.

ie.

f(x)= x²x>=0

-x² x<0

f'(x)= 2x x>=0

-2x x<0;

at x=0, f'(0+)=0, and f'(0-)=0. this shows that in (-1,1) the f'(x) becomes zero once. for a function to be strictly increasing f'(x)>0, ie. it is never equal to zero. therefore the fiitjee solution is wrong. someone let me know if i am right.

great, u will be in the top 500

The match the coulmn had the option xIxI. according to me, the graph is continous and diffrentiable in (-1,1), but at x=0, the slope is equal to 0.

Hence it is not strictly increasing( for a strictly increasing function f(x), f'(x)>0 for all points in its domain). please tell me if iam right. because of this option, i am losing 6 valuable marks.

around 218. buffer of around 15. what about you, and where are u from. im from navi mumbai

thanks a lot.

arvindrock@gmail.com

OH, yes. sorry for troubling you. i did not strike me that the string is being vertically pulled up. sorry

the N is protonated, hence it becomes deactivating. can someone ask their teacher and tell me their answer

what about the vertical component of tension?? which force is cancelling it out?

let me know, great maruti.