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hehehe plz type the Q properly

How long NO RESPONSE!!!

i guess arjun is right............

The answer cant get too complex...

no that cant be

they give d1= 1 + 1/7(remaining medal )

= 1 + 1/7 (m - 1)

DAy two d2 = 2 + 1/7 (m - 2 -d1)

Day three d3 = 3 + 1/7 (m - 3 -d2)

.

Day n dn= n + 1/7 [m -n - d(n-1)]

Sum of all the medals m = [(1+2+3+.........n) + 1/7{ nm - (1+2+3...+n) - (d1+ d2+ d3+.......d(n-1))}

goes on.......

Super Cool!!! POst 'em all !

yes it is a variable........ But the answer shud be only in terms of a,b and c ...

The answer right above is almost correct..........

Thanks allllllllll of you for makin it much simpler !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

If a and b are first terms and c the last term of an AP . a+b+c= ??

yes u r right thank you !

5i+6??

If a,b,c and p are disticnt real numbers such that:

(a² + b²)p² - 2(ab+bc)p + (b² + c²) <= 0

then a,b,c are in what kind of progression? AP, GP or HP?How or why?

hey.. thanks a lot!!

Thanks again!!!

nope hehehe ......... i guess the method has to be a lil' simple cos this problem comes under "not so difficult" kind of questions........

thanks a lot .........