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Was that applause enough for the piece of beauty or was it too simple for the  ?
EXCELLENT WORK.....
Can't clap anymore hand is beginning to pain.
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Yes answer has been posted before.Post your solution.I think you can do it.
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Let the natural length of spring be l
cos 37 = 4/5
So 1/2 m v^2 = 1/2 kx^2
cos 37 = l/h
4/5 = l/h
x = h/4
From the diagram
cos 37 = 4/5 = AC/AB = h/l
So l = 5/4 h
So extension = h/4 = x
So velocity = v = x (k/m) = h/4 (k/m)
cos 37 = 4/5 = AC/AB = h/l
So l = 5/4 h
So extension = h/4 = x
edit : diagram attached
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Yes good solution could be done in a little shorter way
x1 + x2 + x3 + ...+ xn = 271
x1.x2.x3.x4.....xn = Product = P
P will be max when x1 = x2 = x3 =...... xn
So P = (271/n) ^ n
ln P = n (ln 271 - ln n)
Differentiating,
1/P dP/dn = ln 271 - ln n - 1
or ln (271/en) = 0
271 = en , so n = 100 for prod to be max.
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SORRY got it.....
Can't delete it now.
Please don't mind.However good for practice...
answer is b.
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[x] [0] ln cot (  /4 - k1x) / tan k2 x =1
a.) k1 = k2 b.) 2k1 = k2
c.) k1 = 2k2 d.) k1 = 4k2
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In how many parts can 271 be divided so that their product is maximum?
a.) 100 b.) 90
c.) 10 d.) none of these
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f : R  R be a function defined by f(x+1) = (f(x) - 5)/( f(x) - 3)  x  R then which one of the statements are true :
a.) f ( 2006 ) = f ( 2010 ) b.) f ( 2008 ) = f ( 2002 )
c.) f ( 2006 ) = f ( 2002 ) d.) f ( 2006 ) = f ( 2012 )
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@avi i think its pretty simple to draw the graphs....and with sine function having its max value at 1 its enough to understnd from those graphs that they will never meet.However elastiboysai thak u again for posting the graph(i had told him to do it for me).And yeah deedee is also correct.
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Better would be to plot the graph
y = 5^x + 5^-x will be actually a parabola with its vertex at (0,2) and will never intersect with y = sin e^x.So no solutions.
someone please attach the graph.
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good ones...but offensive language shouldnt b used i think.
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Can u proceed widout integrating?Experts please come forward.
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Ok i give u the answer
Its 2l/a .
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No my dear brother u r wrong! 
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