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THE ans is Ti - S1/2

IS THE ANSWER 56 ??????

learner the error u made is finding V as .19 Its .1973684211
put V as UF/U-F to avoid approx

Sorry adi the formula you used is applicable only if d is negligible when compared to focal length

The correct ans are .308 , .148
-.058, .0367

Check it for urself !!!!
cheers

Dont go by the answer in the book . It may be wrong or you may have typed 6 ft instead of 6 m or 1.5m inplace of 1.5 ft

Force is split into 2 components bcos horizontal comp balances torque and vertical comp balances weight. In the fig which ramyani gave the horizontal comp must be opp directed to maintain hor eqm

both assertion and reason are incorrect

A simpler solution is
Tangent is Xcos?/2 + Ysin?/4 = 1
It passes thru centre of circle 2,4
Therefore cos? + sin? =1
? = pi/2 or 0 is general sol

Ramyani though u gave ans as 43 its wrong bcos u ignored the feet- metre conversion

on balancing torque about one corner on hindge side

(2*fcost + 2*fcost)* .3048 = 80*0.75

fcost = 49.2 --------1

on balancing forces

fsint + fsint =80

fsint =40 ---------2

using 1 and 2

f=root(40^2 + 49.2^2)

=63.4 N

Or maybe Ramyani gave correct ans to a wrong question

Its not infinite
ITS
(f/f-1)^2 *((M+m )/ M)* V

Varun u wont get solutions unless u rate them

kbanagar slope of xt graph is VELOCITY

Shinee ur approach in analogy with velocity i only approximately correct though it gets the ans within the options

Here you can solve it usin integration

dA/dt = .5 is rate of change of acc
acc at any time is 2 - .5 t
vel at any time is 2t - .25t^2
dist travelled is t^2 - (t^3 /12)
when t is 4 dist is 32/3
I hope you agree????

in the wat

Ans on fluid mechanics

jus kidding !!!! ?????

Formula for rot of axes is
X= (xcosO - ysinO)
Y= (xsinO + ycosO)
If eq of line is sometin else apply the shift in axes as X+ h and Y +k

gud question