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but the tangential acc is also a component of gravitational acc and hence only g and centripital acc should be taken into account..
the ans should be B.

ok.. the numerator is under root and hence must be positive..

the base of log is 0.4 which is less than 1 and hence

(x--1)/(x+5) < 1

on solving we get,

x> --5

and the no. in log should be greater than 0 hence,

(x--1)/(x+5) > 0.. on solving we get,

x > 1 & x< --5

now, the denominator should be a non zero number there fore,

(x+6)(x--6)

0

which gives x cannot be 6 or --6

by taking intersection of the highlighted ineualities.. u'll get the ans..

(plz rate)

the ans is A..
if its correct then inform me i'll send sol.

thankyou.

car rolls on the path and hence greater frictional force must be helpful in increasing vel of car n not decreasing.. hense it cant be because of it..

here is the sol of ques 2...

let the sum of all the ages be S.

and individual ages be x1,x2,x3............x10

now,

S -- x1 = 82

S -- x2 = 83

''

S -- x9 = 92

--------------------

adding,

9S -- ( S -- x10) =783

=> 8S + x10 = 783 ------------(1)

now we know S -- x10 = p(where p is one of the given sums)----------(2)

adding (1) n(2)

9S = 783 + p

=> S = 87 + p/9

hense p must be multiple of 9 and hence 90..

there fore S=97

hense find x1,x2... by using privious equations.

plz plz rate me if u got the solutoin and if u liked the method...

is the ans is x

(1,

) --(6)..?

if its wrong then plz inform me n if correct then i'll send u my solution.

what is the resultant amplitude and phase of vibration.

S = Acos(

t) +A/2 cos(

t +

/4) + A/4 cos(

t +

) + A/8 cos(

t + 3

/2)

Consider a fixed ring shaped uniform body of linear mass density

and radius R. A particle at thje centre of ring is displaced along the axis by a small distance, show that the particle will execute SHM under gravitation of ring & find its time period neglecting other forces.

plz use more brackets so that ur ques will be clear..
i mean im not getting which term is multiplyed or devided by which...

yes.. i got it..
thankyou.

no.. ans is 5cm

A body of mass 1Kg is suspended from a weightless spring having force constant 600N/m. Another body of mass 0.5 Kg moving vertically upwards hits the suspended body with a velocity of 3m/s and get embeded in it.What is the amplitude of motion?

i know it is simple but still im not able to solve it...

the correct ans should be B.

because when bob is at this position, it has a component of centripital acceleration and one of gravitation.. hense resultanant should be in this direction..