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Catalogs Discussion Forums -> Algebra -> proof of fermat theroem -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
1 replies   

are you asking the proof of


if p is a prime number then (a_1+a_2+a_3+\cdots+a_n)^p\equiv (a_1^p+a_2^p+\cdots+a_n^p)\mod\ p ?


Here it is:


(a_1+a_2+a_3+\cdots+a_n)^p=(a_1+b_1)^p 


where b_1=a_2+a_3+\cdots+a_n\equiv(a_1^p+b_1^p)\mod p


\equiv(a_1^p+b_1^p)\mod p


\equiv[a_1^p+(a_2+a_3+\cdots+\a_n)^p]\mod p


\equiv[a_1^p+(a_2+c_2)^p]\mod p where c_2=a_3+a_4+\cdots+a_n


\equiv (a_1^p+a_2^p+c_2^p)\mod p


continuing like this we get (a_1+a_2+a_3+\cdots+a_n)^p\equiv (a_1^p+a_2^p+\cdots+a_n^p)\mod\ p


 


Or  if you just want the proof of (a+b)^p\equiv (a^p+b^p)\mod p

Catalogs Discussion Forums -> Algebra -> solve this equation.... plzzzz... -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   
OK this one has already been posted. Searched it : http://www.goiit.com/posts/list/algebra-open-challenge-to-all-community-members-and-experts-73653.htm

Se hsbhatt sir's solution. It is perfect.
Catalogs Discussion Forums -> Algebra -> solve this equation.... plzzzz... -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   

Let x=a2 and y=b2


So now a+b2 =7 and a2+b=11 so b=11-a2


And a+(11-a2)2=7


a^4 - 22a^2 + a +114=0


And a=3 is its solution. So x=9 and y=4

Community shelf Community shelf -> Find the mistake -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
9 replies   
x^2 = x+x+x+x+................x this is in correct as x is not a constant. So as x changes the number of x also changes
Catalogs Discussion Forums -> Differential Calculus -> 2 becomes equal to 1 =( -> Go to message
This Post 2 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
7 replies   
"mathematically flawless"????

Who said to you that it is mathematical flawless???????

The flaw is that these rules are not for 1 or infinity.
Catalogs Discussion Forums -> Algebra -> For the Inequality Enthusiasts - I -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   
first we don't have to use AM-GM inequality or the sign will be other way around.
Catalogs Discussion Forums -> Differential Calculus -> 2 becomes equal to 1 =( -> Go to message
This Post 12 points    (Olaaa!! Perrrfect answer.   in 3 votes )   [?]
7 replies   
The fallacy lies in ignoring the fact that the number of x's being added is not constant. Not only is x changing; the number of x's is also changing.
Catalogs Discussion Forums -> Differential Calculus -> 2x=x -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
3 replies   
The fallacy lies in ignoring the fact that the number of x's being added is not constant. Not only is x changing; the number of x's is also changing.
Catalogs Discussion Forums -> Algebra -> quadratic -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
4 replies   

well the subject is quadratic :P 

Catalogs Discussion Forums -> Algebra -> question -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
8 replies   

please see the person's class/std before posting any replies.

Catalogs Discussion Forums -> Lounge -> a mathematician's love letter -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   

not again..


Posted many times:  http://www.goiit.com/goiit.htm?module=search&action=search&clean=1&search_keywords=Mathematician+Love+letter&search_terms=all&search_forum=&sort_by=time&sort_dir=DESC&search_cat=

Catalogs Discussion Forums -> Algebra -> solve for x -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
4 replies   

(\sqrt{3}+1)^{2x}(\sqrt{3}-1)^{2x}=2^{3x}\\\\\Rightarrow (3-1)^{2x}=2^{3x}\\\\\Rightarrow 2x=3x\\\\\Rightarrow x=0

Catalogs Discussion Forums -> Algebra -> solve -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
7 replies   

the question is   =  9x-3


And you have taken (4x^2+5x+1)^1/2 - 2(x^2-x+1)=9x-3


this should be (4x^2+5x+1)^1/2 - 2[(x^2-x+1)]^1/2=9x-3

Catalogs Discussion Forums -> Algebra -> determine the maximum value -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
2 replies   

Q2) This is a type of  mordell's equation and it has only one solution for the constant k=2


 (5,3) is the only solution for this

Catalogs Discussion Forums -> Differential Calculus -> find dy/dx at x=1when siny raised to d power sin((90)x)+(root3)/2[(se cinverse)2x]+2 raised -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
11 replies   

in the reply box see the right hand side top . Screen shot:

 
 
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