in this questions we have 3 cases

x>1              (x/x-1)+x=x²/x-1             x not equal to 1

we get 0=0 i.e... true for all x>1

0<x<1              (x/1-x)+x=x²/1-x         

we get x=0

x<0      (x/x-1)-x=x²/1-x

we get x=0

so solution is {0}U{(1,infinity)}. cheeeeeerrrrrrssss

 ur question is not clear yaar i took the two sphere has same centre and has radius R₁,R₂respectively.

when a sphere is earthed the pottential at that point is 0

hence V₂-V₁=V₂=K(q₁+q₂)/R₂

cheeeerrrssss

2)(1-i)ⁿ=(1+i)ⁿ

cis(-npi/4)=cis(npi/4)      (2^n/2(1/rt2+i/rt2)ⁿ) 

2isin(npi/4)=0

npi=4m(pi)

n=4m

n should be multiple of 4.

cheeerrrsss

let f=2^x/1+2^x+1

dy/dx=df/dx(1/1+f²)

f(1+2^x+1)=2^x

df/dx(1+2^x+1)+f(2^xlog2)=2^xlog2

find the value df/dx=2(log2)/9

f at x=1 is 1/3

dy/dx=(log2)/5

cheeerssssss.

(1-3(sinxcosx)^2)=1/4

(sinxcosx)^2=1/4

(sin2x)^2=1

sin2x=+-1

hence x=(pi/4,3pi/4,5pi/4,7pi/4)

if iam right plzzz rate me cheeeeerrrsss

substitute y^2=4x in the 2nd equation

u get (x-1)^2=0

imply there r 2 roots but equal

so, the lines do not intersect but touch at 2points i.e.. (1,4) &(1,4)