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hello everybody,
this question is to rukrukkhan....... how did u get to know abt this?
plss answer this so that u can make us believe what u said is true....personal request from my side...... thank you.
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hi,
I guess thats not bad decision at all bcoz u have very good colls UNDER aieee n IIT .secondly once if u r thoroughly prepared for IIT aieee would be a cake walk for you.Ur 12th marks wont at all effect ue performance in JEE .so dont be worried.
i feel u should go for it ,but YOU should see that every concept u learn u have got 100%clarity in it.if u can do that then thr is no one who can stop u from ur bright future.
and moreover since u are from CBSE u will have an edge over others.
ALL THE BEST .
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i feel the question is wrong.the average veloctity is zero if it comes back to a.i guess u r speaking of average veloctity.pls let me know if im wrong .
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hi sneh,
dont worry ...... u might just be called for the counselling...u have to wait for the first counselling to get over n then they will call the later students (rank>5000) for counsellling .
last year to fill their 5000 seats they had to call ranks uptilll 14000 ...so keeping that in mind u might just be well in.thr's no procedure to follow....just wait for their call for counselling...it MIGHT be in the first week of june.
ALL THE BEST..:)
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hi, can anybody pls mention the date when ISI(Indian Statistical Institute) results will be given.
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hi friend,
U have taken a very bold decision .........i mean it....firstly have a killer instict towards ur approach..... secondly n most importantly do not think of the time u have to spend with books ..think of the time that u will have to take to understand a particular topic to that an extent that u will never have to struggle with it again..this is very important ...u have to get ur concepts right ........ a perfect understanding must be achieved ....... it should be all clear in ur mind......
now u will know how much time to spend a day .....always remember this is not ur BOARD exam whr if u stay some 8 hrs or 12 hrs u will score greater ...it all lies in ur depth of understanding in concepts......
another fact strt with chem its easy if u understand and also mind u that its way tooooo scoring than the other two subs....and also u have to qualify in indivisual cutoffs in each sub so never ever leave a subject untouched....
i hope now u can devise a proper n well suited time table for urself and aim high to achieve even higher...
i hope my piece of advice has helped you ...
ALL THE BEST
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hi ,
along the length of the rectangular wire no emf is produced which can be verified by the expression
E = l (v*B) where l= length , * is cross product.
now coming to the breadth sides, u apply the same formula ,
at the closer end ,
u will get some E1 at the farther end u will get E2 , now this can be got by the previous formula.
now the circuit can be made like two cells of diff emf's E1 , E2 in series.
net E=E1~E2
hope u have got it.
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hi,
if its placed on the corner of a cube ,then arrange 7 more such cubes around that point such that ,now the enitire structure is a cube again n the point charge is at the centre of the bigger cube.so now apply gauss law ,
flux=q/8eo where e0 is episolnot.
its 1/8 bcoz with respect to bigger cube its 1time but since we have only one cube initially we divide by 8 .
hope u got it.
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hi,
the oil paintings turn Black because of the reaction btw the present lead and hydrgen sulphide from the air to form PbS which is responsible for the black coulouring after some time.
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addy,
i feel personally after writing JEE this yr is that no matter whr u go ,ur work is 90% n the institutions work is abt 10%.so it does not really depend on whr u go or whr ur frnds are running abt .its finally whr everybody lands up in.infact both FIITJEE n Brilliant r good. going to these willl let u remain focussed n m,ore importantly organised n keep reminding u abt ur postion in a group. So the decision is all urs. any further doubts pls nudge me ,i'll reply u here.
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hi,
if u increase the veloctity by 20% ur final velocity is 1.2v
since u apply the same force , the acceleration remains the same..therby
V^2=2as
=> v^2/s=constant
1.2^2/s=1/x
s=1.44x
whr x is the initial distace after which the car stops
therefore,
increase%=(1.44x-x)*100/x
=44%
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let the car take a time t1 to acwuire the velocity v
v=at1
then let it take a time t2 to come to rest
0-v=(-b)t2
the total distance travlled in the trip
1/2at1^2 + vt1 +vt2 - 1/2bt2^2 =s
now the average velocity=total distace / total time
=s/t
here t=t1+t2 .
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