| Message |
|
|
|
a1/3 + b1/3 - 1 = 49 + 20 (6)1/3
=> a1/3 + b1/3 = 50 + 20 (6)1/3 comparing, a = 503
b = 6*203
|
|
|
|
|
f(x)=ax2+bxt+c
f(5)+3f(2)=0
=>[25a+ 5bt +c] + 3[4a+2bt+c] = 0
=>37a + 11bt + 4c= 0 ....................(a)
f(3)=0
=>9a+3bt +c=0 Multilpying both sides by '4'
=>36a + 12bt + 4c = 0 .....................(b)
(b)-(a)
a - bt =0
=>bt =a
=>c=-12a
thrfore, f(x)= ax2+ax-12a thus f(x) = 0
=> a (x2+x-12) = 0
=> x = 3, -4
|
|
|
|
|
the sum of all the pages, including the page torn S = n(n+1)/2
thus, n (n+1)/2 >= 15000
the minimum integral value of 'n', for which the above equation is true is n =173, for which S= 15051
since, the pages torn, wil have consecutive numbering,
p+(p+1)= 15051-15000
=> 2p+1= 51 => p = 25
pages torn = 25,26
|
|
|
|
|
2sinx + 2sin3x=siny............r u sure , its 2 sin x and not 3 sinx???
if its 2 sin x, the question is getting un-necessarily lengthy, n then also, the answer is not guranteed.
for 3 sin x, the solution given by jagdish, is perfect :)
|
|
|
|
|
a rectangular hyperbola is given by xy=c2
differentiating the equation, we have the differential equation: y + y'x =0
degree=1, order =1
|
|
|
|
|
Let the respective speeds be a, b and c.
then when a, nd c meets, 88 (a+c) = 2X11Xpi => a+c = pi/4 .................(1)
when b and c meets, 110(b+c)= 2X11Xpi => b+c=pi/5 .................(2)
now, since a and b are moving in same direction, when they meet after time 't'
t (a-c) = 2X11Xpi .................subtracting (2) from (1)
=> t [(pi/4) - (pi/4) ] = 2X11Xpi
=> t = 440 sec
|
|
|
|
|
A friend function is a function that is not a member of a class but has access to the class's private and protected members. Friend functions are not considered class members; they are normal external functions that are given special access privileges. Friends are not in the class's scope, and they are not called using the member-selection operators (. and –>) unless they are members of another class
|
|
|
|
|
hemang has solved the question already...thanx :)
|
|
|
|
|
whats the question dear :?
|
|
|
|
|
the question has been already solved by prahlad !!
thank u :)
|
|
|
|
|
The catalyst increases rate reaction by providing a different reaction mechanism to occur with a lower activation energy.
It does not affect the position of the equilibria, as the catalyst speeds up the backward and forward reactions equally.
|
|
|
|
|
what do u mean by the 'absolute meaning' of any theorem?
|
|
|
|
|
the question is already solved :)
|
|
|
|
|
If one vector is equal to the sum of scalar multiples of other vectors, it is said to be a linear combination of the other vectors. For example, suppose a = 2b + 3c, as shown below. Note that 2b is a scalar multiple and 3c is a scalar multiple. Thus, a is a linear combination of b and c.
|
|
|
|
|
what is the next term?? a4 +a3b+a2b2+ ab3+b4 or, a4 +a3b+2a2b2+ ab3+b4 Pls specify!! |
|
|
|
|
domain of sin-1(x-x2)
-1 =< x-x2< = 1
x2 - x - 1 =< 0
=> ( x-1/2 )2 - (5/4) =< 0
=> [ x - {(1-sqrt5)/2} ] [ x - {(1+sqrt5)/2} ] =< 0
=> [ x - (- 0.6 ) ] [ x - 1.6 ] =< 0
=> x  [ -0.6, 1.6] .....................(A)
domain of (1-(1/ IXI))1/2 firstly, IxI should not be 0 => x (not =) 0 .................(i)
1-(1/ IxI) > = 0
=> 1 > = (1/ IxI)
=> |x| > = 1
=> x =< -1 or x >= 1 ..........................(ii)
combining (i) and (ii), domain : x (-infinity, -1]  [1, infinity) .............................(B)
domain of 1/[x2-1] [x2-1] (not =) 0
=> (x2-1)<0 or, (x2-1) >=1
(x2-1) < 0
=> x (-1,1) .............................................(iii)
(x2-1) > = 1
=> x  (-infinity , -sqrt2 ]  [sqrt2, infinity ) ..........................(iv)
combining (iii) and (iv), x (-infinity , -sqrt2 ] (-1,1) [sqrt2, infinity ) .....................(C)
as all the three conditions given by (A), (B) and (C), should be fullfilled, the domain of the entire expression can be found out by taking the intersection of the three :)
|
|
|
|
|
cos # = 2.4 / 3
= 4/5
=> # = 37 degrees
now tan (180-$) = slope of the line = -3/4
=> $ = 37 degrees therefore, the slope of the required line = tan @ = tan (90- $ - # )
= tan (90- 74)
= cot 74
now u have the slope, and the point.. u can write the equation of the line :)
|
|
|
|
|
two species are isolobal, if the number, symmetry properties, approximate energy and shape of the frontier orbitals and the number of electrons in them are similar – not identical
|
|
|
|
|
STRUCTURED QUERY LANGUAGE... It is a standard language for accessing and manipulating databases
|
|
|
|
|
in the bigger triangle sin @ = R / (L2+ R2)1/2 ....................(A)
cos @ = L / (L2+ R2)1/2 ....................(B) Now the area of the required triangle (the shaded area) = b X h
in smaller triangle, with angle @ .... h = L cos @ and b = L sin @
therefore, the area = L2 sin @ cos @ substituting values from (A) and (B)
= RL3 / (L2+ R2)
|
|
|
|
E-Store
