goIIT: IIT JEE AIEEE CET WBJEE VITJEE BITSAT IIIT AICET Engineering Entrance Experts, Student Discussion Community, IIT JEE Preparation Online

hi,

consider that origin lies in acute ang region.drop perpendiculars M1,M2 from origin to these two lines.now since ang between lines is acute,angle M1OM2 is obtuse.

that implies, vector OM1 . vector OM2<o (dot product)

therefore, by writing in vectorial form we get the result as nc(al+bm)<0

sorry that i didnt give u the complete steps thats because its somewhat big and also has difficult notations which i am not able to type here.

sorry,

its nc(la+mb)<0

and for origin to be in obtuse ang region it is nc(la+mb)>0

hi,

the condition is la(mb+nc)<0

hiiiii,

i accept the otherr methods but i have one,

summation cosA/sinB sinc = summ.(-cosB+C)/sinBsinC

=summ.(1-cotBcotc)=3-summ.(cotBcotC)=3-1= 2

i hope u have understood cis and trans.

in E,Z nomenclature there is a priority order.if the top priorty groups are on same side ,it is Z-..... if they are on opp sides it is E-...

hi,

i am an IIT-2008 aspirant.morrison and moyd is not presccribed for IIT or AIEEE.so i would recommend u not to follow morrison and boyd but if u r quite intelligent and bright u can work hard on it to understand it.i would prefer O.P.Tandon organic chemistry by arihant publications.its purely for IIT so u can understand from it clearly.

hi sagar,

i am from hyderabad.i am in XI class.i have also joined an institute here in hyderabad.i am doing well.how about u??

lets be friends.

my email id is tiger_3846@yahoo.com

pls do contact me.

yes alkenes undergo addition reactions.the species which contain double bond b/n simillar atoms they are called as neucleophiles.they undergo electrophilic addition reactions.

hiii,

exactly neelesh.u r exactly right.i agree with u.

thanks for that aakriti

hi,

hybridisation is a concept which must be applied to all compds.

like the electronic configuration which is simillar for all atoms.the bonding is explained by hybd.ok it may contain the req no of electrons but how can u explain its other properties??

hey aditya,

i think it undergoes ring expansion.just think about it.

hi,

when the given compound undergoes electrophilic substitution +ve charge is on the carbon adj to the cyclo pentane ring.So it undergoes ring expansion ti form methyl cyclo hexane carbocation.then chlorine atom attacks the +ve charged C-atom to form 1-chloro-2-methyl cyclo hexane.

no.tri phenyl tin hydride can't reduce carbonyl compds.but LiAlH4 and NaBH4 can reduce.

ohh i did it in a hurry