FIND THE POINTS ON THE ELLIPSE x²/a²+y²/b²=1 SUCH THAT THE TANGENT AT EACH OF THEM MAKES EQUAL ANGLE WITH THE AXES.ALSO PROVE THAT THE LENGTH OF PERPENDICULARS FROM THE CENTRE  TO THESE  TANGENTS IS [(a²+b²)/2]^1/2.

ANSWER IT QUICKLY

C'MON SOMEBODY ANSWER

THE CURVE WITH THE PARAMETRIC EQUATIONS x= -1+2 cos ,y= 1+5 sin  represents a--

an ELLIPSE

A HYPERBOLA

A PARABOLA

AND WHY???

→A spherical cavity is made in a lead sphere of radius R such that it’s surface touches the outside surface of the lead sphere and passes through its centre .The mass of the lead before hollowing was M. What will be the force of attraction that this sphere would exert on a particle of mass of m, which lies at a distance d from the centre of the lead sphere on the straight line joining the center of the sphere and centre of cavity?

→Consider an attractive force of the form Fr = -K/Rⁿ where K is a constant.For a stable circular orbit t o exist, what should be the range of value?s? of n?