sign up I login
 advanced
refer a friend - earn nickels!!
FORCE_IIT   FORCE_IIT is offline FORCE_IIT's messages in the community
Message
Catalogs Discussion Forums -> Mechanics -> SOMETHING?? -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   

Hey,community if you like this concept then please rate me here.

Catalogs Discussion Forums -> Mechanics -> SOMETHING?? -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   

We know that a vector quantity has a magnitude and a direction whereas a scalar quantity only has magnitude. But according my concept - a scalar quantity has a magnitude and capability to possess any one of the all possible directions.


Is this true sir? If no then what is wrong in it? Please tell me.


 


 

Catalogs Discussion Forums -> Electricity -> HELP?? -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
10 replies   

 IN WHICH DIRECTION DOES ELECTRIC POTENTIAL DECREASE IN A UNIFORM ELECTRIC FIELD?

Community shelf Community shelf -> CHIRALITY ,ENANTIOMERS, STEREOISOMERS AND ISOMERISM -> Go to message
This Post 7 points    (Olaaa!! Perrrfect answer.   in 2 votes )   [?]
0 replies   

 


Enantiomers


 


Chirality


 


STEREOISOMERS are  molecules that have the same connectivity but differ in their spatial arrangement of atoms. We see that the rigidity of double bonds give rise to one type of stereoisomerism, cis-trans isomerism. However, it turns out, cis-trans isomers form only a small subset of stereoisomers. A more important type of stereoisomerism arises from molecules that are chiral. 


 


We have some intuitive notion of what it means for an object to be chiral, which is a Greek word meaning "handed". Consider the relation between our left and right hands. They appear to be the same, and yet there are clearly some ways in which they are distinct. For example, a right glove that fits easily over our right hand will not fit over our left hand. We would have a hard time fitting a left shoe over our right foot. A pair of right-handed scissors works fine in our right hand but feels awkward when we try to use our left hand.


 


What does it mean for an object to be chiral? To answer this question, again consider our left and right hands. The objects look identical; in fact theyare mirror images of each other. However, they are not the same. The test used to determine whether two objects are identical is superimposability. That is, can two objects be placed in the same space in such a way that all of their components overlap? Try the test of superimposability on your left and right hands, and you should see that they are not superimposable. This allows us to define what it means for an object to be chiral:


 


a chiral object is one that is not superimposable on its mirror image.


 


Conversely, an achiral object is one that is identical (superimposable) to its mirror image.


 


How can we tell whether a given object is chiral? The most straightforward way to determine whether a given object is chiral is to draw or visualize the object's mirror image and see if the two are identical (that is, superimposable). If the object contains an internal plane of symmetry then it must be achiral. However, as we shall see, the converse is not true: an object that has no internal plane of symmetry may also be achiral.


 


CHIRAL MOLECULES


 


Molecules, like other objects, can be chiral or achiral. For example, build a model of 2-butanol (butane with an -OH substituent on the second carbon) and its mirror image:







STEREOGENIC CENTERS


 


What makes a molecule chiral? It turns out that in the majority of cases chiral molecules result from carbon atoms that are bonded to four different groups. For example, C2 in 2-butanol is attached to the four distinct groups -H, -Me, -Et, and -OH. There are two different ways to arrange four groups about tetrahedral carbon, giving rise to chirality. (In fact, chiral molecules gave chemists evidence that carbon is indeed tetrahedral.) Such a carbon atom is called an asymmetric carbon because it lacks a plane of symmetry. Asymmetric carbons are also called "chiral carbons". Because asymmetric carbons give rise to stereoisomerism, they are stereogenic centers or stereocenters. Technically, there are other structural motifs that are stereocenters beside asymmetric carbons, but in practice the term "stereocenter" is used in place of "asymmetric carbon" to denote a carbon bonded to four different substituents.


 


 (R)/(S) NOMENCLATURE


 


The goal of nomenclature is to allow chemists to unambiguously identify the structure of any molecule given its name. The presence of stereoisomers presents a special problem in this regard. For example, given a particular molecule of 2-butanol, how can we name it so that the name conveys its handedness? How can we convey exactly which enantiomer of 2-butanol we're talking about? Furthermore, what about molecules that contain several stereocenters? What is needed is a nomenclature system to designate the absolute configuration at each stereocenter.


 


The term "configuration" refers to the fixed spatial positioning of bonds at a particular stereogenic carbon atom. We should  not confuse "configuration" with "conformation". Unlike conformations, which are constantly equilibrating back and forth between forms, configurations are fixed and do not change unless bonds are broken. The configurational designation is absolute in the sense that the exact three-dimensional structure of the molecule can be reconstructed using the name alone.


 


In order to specify the absolute configuration at any stereogenic carbon, first identify the four groups attached to it and assign priorities to them using the      Cahn-Ingold-Prelog convention:


 


 



  1. Examine the atoms directly attached to the stereogenic carbon. Groups attached with atoms of higher atomic number receive higher priority.

  2. In the case of isotopes, assign higher priority to the group containing the atom of higher atomic mass.

  3. When the attached atoms are identical, move down the next branching bond of the highest priority, and repeat until a difference is found.




After assigning priorities, look at the molecule so that the group of lowest priority is facing away from us. Now trace a circular path from the group of highest priority to the group of second priority to the group of third priority. If this path is clockwise, the stereocenter has an (R) configuration. If the path is counterclockwise, the stereocenter has an (S) designation.    Try to physically superimpose these models and we'll see that they're not superimposable. This means that there are two distinct versions of 2-butanol, a right-handed one and a left-handed one. Each version of 2-butanol is a chiral molecule. What is the relation between them? The two molecules are clearly isomers, and since they have the same atomic connectivities they are stereoisomers. Unlike cis-trans isomerism, this stereoisomerism arises from the ability of m   olecules to be chiral. A chiral molecule and its non-superimposable mirror image are special types of stereoisomers called enantiomers.


 


 


 


 

Catalogs Discussion Forums -> Analytical Geometry -> bravoo!!! c'mon do it -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
2 replies   

P AND Q ARE TWO POINTS ? AND 2? ON THE ELLIPSE x2/a2+y2/b2=1 .SHOW THAT THE LOCUS OF THE MIDPOINT OF PQ HAS THE EQUATION


 (x2/a2+y2/b2)( 4x2/a2+4y2/b2-3)=x/3


 

Catalogs Discussion Forums -> Analytical Geometry -> BITS 1999.....plzz solve!! -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
21 replies   

((x+ae)2+y2)1/2+((x-ae)1/2+y2)1/2=2a


solve and you get the equation of an ellipse

Catalogs Discussion Forums -> Analytical Geometry -> HIMMAT HAI ? THEN ANSWER IT. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
2 replies   

LET P(acos?,bsin?) BE ANY POINT ON THE ELLIPSE x2/a2+y2/b2=1 .LET S AND S’ BE ANT TWO FOCI AND THE TANGENT AT P MEETS THE X-AXIS AT M .PROVE THAT PM BISECTS THE EXTERNAL ANGLE S’PS.

Catalogs Discussion Forums -> Analytical Geometry -> ANSWER IT....... -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   

FOR THE ELLIPSE x2/a2+y2/b2=1 ,PROVE THAT THE CIRCLE ON ANY FOCAL DISTANCE  TOUCHES THE ELLIPSE.

Catalogs Discussion Forums -> Analytical Geometry -> FIND AREA? -> Go to message
This Post 2 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
3 replies   

When p ia at A or A' area=0, as p starts moving towards the minor axis area increases and therefore area is maximum at (0,+b) or (0,-b) -


hence area=1/2[a(b-0)+0+(-a)(0-b)=ab

 
 
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya