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raju ban gaya gentalmal

duplicate to

http://www.goiit.com/posts/list/general-drop-or-continue-68574.htm

what exactly you want ??

give me soemtime.,

let me find out something for you

The latest blog of pathfinder is out here. I think it helped me to take some decisions. What about you friends ??

k < ( x - 1 )

Case 2

k - x > 1

k > ( x +1 )

so for ( x - 1 ) > k > ( x +1 ) the abolve equation will have non real solutions

cheres

Well I have not tried, but here is a technique, may be i am wrong
For 6 numbers, total possible numbers are 6! = 720

take half of the the average numbers = 333,333 and other half = 444,444

So the sum can be S = 360 x 333,333 + 360 x 444,444

Try to find out the solution with the first method and compare, may be you get both the answers matched

Cheers

As choosing a set of 5 out of {1,2,3,4,5} is possible in only one way

12345

So number of all different numbers can be formed by this set is 5! = 120

Now imagine placing each of these 5-digit numbers on top of each other in a long list to be added manually. Each of the digits 1, 2, 3, 4, and 5 will appear equally often in each of the units, tens, hundred, thousand and ten thousand columns. There are two ways to proceed...

1.

As 120/5 = 24, each digit will contain twenty-four occurrences of each digit and so each column would add to 24(1+2+3+4+5) = 360.

In adding the units column we write 0 and carry 36.
In the ten column we get 360+36 = 396: write 6 and carry 39.
In the hundred column we get 360+39 = 399: write 9 and carry 39.
In the thousand column we get 360+39 = 399: write 9 and carry 39.
In the ten thousand column we get 360+39 = 399: write 9 and carry 39.

Hence the sum is 39 9 9 9 6 0 = 3,999,960.

2.

Its a tricky one

As the mean digit in each column is 3, each number is 33333, on average. Hence the sum is 120

33333= 3,999,960.

Now you can try to solve this one

Find the sum of all possible permutations of k digits taken from {1,2,3,...,n}, if the repetition is not allowed.

Cheers
Rahul

f(u+v) + f(u-v) = 2 . f(u) . cos(v)

put u =

/ 2 - x
v =

/ 2

so the equation becomes

f(

/ 2 - x +

/ 2 ) + f(

/ 2 - x -

/ 2) = 2. f(

/ 2 - x).cos(

/ 2 )

f(

- x) + f(-x) = 0 ( as cos(

/ 2 ) Answer

From the first law of thermodynamics then heat given to a gas is divided into two things , change is internal engery + the work done by the gas.

So, we write the internal energy of the gas in terms of constant volume, because if some heat is given to the system then at constant volume the work done by the system will be zero (

P dV ) , and all the energy will be used to increase the internal energy of the system that will be nc(at constant volume)t[where n is the no of moles and t is the change in temperature].

Here

initial velocity u_x = 2 m/s
acceleration a = a_xi + a_yj = 2 m/s²

so a_x= 2 . cos60 = 1 m/s²a_y = 2. sin60 =

3 m/s²

So the displacement after 2 seconds

S_x = 6 m
S_y = 2

3 m

and the magnitude of displacement is S =

36+12 = 4

3 m

Lets say curve has the equation y = f(x)

Now the equation of tangent at any point on the curve is given by

Y - y = (dy/dx)(X - x)

Now say, this line meets x axis at point (a,0) ...so the points where it meets y axis is (0,4/a) ( As the area of triangle is 4 )

By putting these two points in the equation above and eliminating the value of 'a' we get --

x²dy - xydy -ydx + 4dx = 0

x⁴( x²dy - 2xydy)/x⁴ + xydy - ydx + 4dx = 0

x⁴ d(y/x²) + (xy - y + 4)dx = 0

x⁴ . y/x² + y. x²/2 - xy + 4x = C

This curve passes through (1,1)..... By putting the this value in curve we get the final equation of the curve

3 x²y - 2 x y + 8 x - 9 = 0 Answer