If a and b are the roots of px2 + qx + r =0 then roots of eqn..
a) (p-q+r)x2 + (q-2r)x + r = 0 are a/a+1,b/b+1
b) px2 - qx + r =0 are a-2b,b-2a
c) prx2 - (q2 -2pr)x +pr -0 are a/b,b/a
d) px2 + 10qx +100r =0 are 10a,10b
more than 1 answer is correct
but i dont havthe solns with me..plz solve