condition for concurrency, delta =0
| a 1 1 |
| 1 b 1 | = 0
| 1 1 c |
applying
(C2 - C1) and (C3 - C1)
delta = a(1-a)(c-1) - (1-a)(c-1) - (1-a)(b-1) =0
dividing by (1-a)(1-b)(1-c), we get
a/(1-a) + 1/(1-b) + 1/(1-c) =0 , v get
1/(1-b) + 1/(1-c) = 1a/(1-a)
add 1/(1-a) to both sides,
1/(1-a) + 1/(1-b) + 1/(1-c) = (1-a)/(1-a) = 1