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cant u see above solution by Kaymant sir!!!!!!!!!11
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i too preparing for jee.
but i think droping second semester will create pressure and heard that it sometimes creates proglem during placement(current college).second sem. topics will improve ur dyanamics,calculas,electrical,modern phy.
and studying in engineering college and preparing for top eng. college makes mentally strong.
best of luck.
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awesome ....last one was really funny !
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analytic aproach and visualising things makes u an 'IITIAN.'
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civilians r better paid than archi people
donno abt aero,
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it depends on ur frame of refernce.
for a partical shot,
if x axis is along the shaduw(projection of ball on the ground)of the ball,then its 2-D. I
and 3D,if its not d case.
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ur condition is always true wen body is in equlibrium only.
if body is oly in rotational motion;
-take torque abt COM.
if it is in both translatory motion;
-take abt the COM or INAR(instan. axis ..)
all above have special prop. -fix dir. of velocity or zero vel.
justification u need not to bother,in 1st yr b.tech u wd b taught in engneering dyanamics(full semester).
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doing ncrt sincerly(concepts) with good accuracy and speed will fetch below 3000.
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another method to solve the circuit.
this we r thought in 1st year of engineering( basic electrical tecn).
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it states that light always takes the shortest path between the given initial and final positions.
snells law is the result of this theorem.
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how can u clear JEE without maths!!!!!!
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i think both of the gas samples were in the similar container of same volume,then we can use the given relation.
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yes it depends on the frame of reference.
suppose u r in train,then u dont have KE wrt an observer in the train.
but for an observer in the ground u have KE.
but finding is of no use,
since evry theorm requires only inertial frame !!!!!!
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E=-d/dx(-ax^3+b)
=3ax^2.
as we can see field is along the x axis.
so take the guassian closed sys. as cuboid(say of unit height) of of widt dx
let A the area of face perpendicular to axis.
(E2-E1)A=q/epsilon,wer E1 n E2 r field at a distance x n x+dx frm origin where cuboid is present
E2=3a(x+dx)^2,E1=3ax^2
after simplification
q=epsilon*A*6axdx
rho=q/volume
=epsilon*A*6axdx/A*dx
=6ax*epsilon
!!!!!!!!!!!!!hope u understood!!!!!!!!!!!!!!!!!!
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ganpat ji,u did calculation mistake in finding v.
v=root.2*10*.45
=3 m/s.
iitaspirant wats the ans?
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how can we compare the hydration energy of any anion and cation without having idea abt their relative size,charge density ?
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NEVER heard during my prep.not in the syllabus!!!!!!
just google it -
The isolobal principle in organometallic chemistry devised by Roald Hoffmann aims to improve the understanding of chemical bonding in molecules by identifying molecules that share a common frontier orbital type, approximate energy and occupancy just as isoelectronic molecules share the same number of valence electrons and structure [1]. When representing pairs of isolobal structures, they are connected through a two-pointed array with half an arrow below.
The methyl radical is isolobal with the metal carbonyl species manganese pentacarbonyl Mn(CO)5 because both molecules have a single electron in a hybrid orbital pointing away from the plane of the molecule (though they are not isoelectronic). This resemblance is reflected in the chemistry of both molecules. As the methyl radical can dimerize to ethane, Mn(CO)5 can dimerize to (CO)5Mn-Mn(CO)5 and both radicals can even form Mn(CO)5CH3.
Scheme 1. Isolobal principle
In the same way iron tetracarbonyl Fe(CO)4 is isolobal with the carbene CH2 because they both have two electrons contained in two hybrid orbitals. methylene dimerizes to ethylene and both fragments can couple to a carbene complex.
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