9.) loss of wt = wt of displaced water = 2

Let the amt of cu = x

So,

36 - x / 19.3 + x / 8.9 = 2

Solving this we get 10.4 x = 343.54 - 320.4

so x = 2.225 gms

 

 

Next one take volume as a variable and find out the answer its simple

 

Mass of man = 60 g

Mass of box = 30 g

Let R' be the app wt of man and T be the correct wt

R' + T = 60 g

T - R' = 30 g

R' = 15 g

So wt shown by machine = 15 g

 

Let the wt applied to get correct wt. be T and R be the normal reacn.

Considering Free body diagram of man,

T + R = 60(g +a) : a = accn of lift

Fbd of box,

T - R = 60(g - a)

So R = 60 g

T = 60 a

But T = 90 g + 30 a

90 g + 30 a = 60 a

a = 3g

So T = 1800 N

 

Hope the thing is clear

Pls do rate me

Thank you sir what about the next one?

 

exponent of 2 in ⁵⁰P₁₀ is

a. 8

b. 9

c. 12

d. 11

 

There are 5 eligible Punjabi grooms of which 3 know Bengali and 5 eligible Bengali grooms of which 2 know Punjabi. There are 5 eligible Punjabi brides and 5 eligible Bengali brides.If an eligible groom is agreeable to marry a girl of his community or knowing her language and brides have no choice, in how many different ways 10 couples can be formed?

Asit das gupta book, page no. A-171, Quesn no 57

Ans : 144000 

so what has it got to do with optics please post your question properly

 

I believe that HCVERMA alone puts u in good battlestead for any examination as the problems are wonderfully conceptual

 

Could people help me out with the bengali bride and punjabi grooms. I dont remember the exact questuion number .It was somethiung like prob no 64 in Asit das gupta.

Ans was 144000

hey dont say that u dnt hav the book or u cant understand the problem as its quite a distinct one.

Few days ago i posted 2 problems about electrostatics and there were no replies So friends please cooperate.

I am posting this from an internet cafe so please understand that i dont have the book with me

Please help

 

hey what do u mean after all about rationalising fractional oxidation numbers?????

the principles and concepts remain just the same

 

COMMON GUYS N GALS WAITING FOR A SOLUTION

WHAT ABOUT THE EXPERTS, WHY DONT THEY HELP

THE QUESTION IS FROM ARIHANT ELECTRICITY AND MAGNETISM LEVEL 2 PROBLEMS BY D.C. PANDEY

 

A non conducting ring of mass m and radius r is lying at rest in the vertcal XY plane on a smooth non conducting horizontal XZ plane. Charge +q & -q are distributed uniformly on the ring, on 2 sides of the vertical diameter of the ring.  A constant & uniform electric field E is set up along X direction.The ring is given a small rotation about the vertical diameter of the ring and released.Find the period of osscillation of the ring

 

Ans: 2 ^[2](mr/4qE)

 

The electric potential varies in space according to the relation V = 3x + 4y.A particle of mass 10 kg starts from rest from the point (2,3.2)under the influence of the field.Find the velocity of the particle when it crosses the X axis. The charge on the particle is + 1 C. Assume V and (x,y) are in SI Units.

 

Ans: 2 * 10 ^-3 m/s  

Please reply with detailed solution.

Interesting question on electrostatics coming

 

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