SORRY FOR THE INTERRUPTION BUT PLZ SEE THIS ::::

 

U'LL WORK UR NUTS OFF TO SOLVE THIS ANOMALY BUT U  WOULDN'T BE ABLE TO.

 

 

 

 

 

ABCD is a square. BE = BC.
PQ bisects CD,AB.
OR is perp.bisect. of DE.
PQ, RO intersect at O.
ANGLE ABE is an OBTUSE ANGLE. ( clearly )

TRNGLE ORD IS CONGRUENT TO TRIANGLE ORE (SAS)
:. OD = OE

TRIANGLE OQA IS CONGRUENT TO TRIANGLE OQB (SAS)
:. OA = OB & ANGLE OAB = ANGLE OBA.......................1

 

TRIANGLE  OAD CONGRUENT TO TRIANGLE  OBE (SSS)
:. ANGLE OAD = ANGLE OBE..............................2
 

ANGLE ABE = ANGLE OBE - ANGLE OBA
= ANGLE OAD - ANGLE OAB..................................FROM 1 & 2

But ANGLE OAD - ANGLE OAB
= 90 °..............................CLEARLY

:. ANGLE ABE = 90 °
However, we've assumed the angle to be obtuse. :. Every obtuse angle is a right angle.