If Sm : Sn is equal to 441:256. what is the ratio of tm: tn equal to?
your options are:
a) 21:16 b) 41:31 c) 31:41 d) 16:21
the formulae to be used in this sum are:
Sn= n/2 (2a + (n-1)d) and tn = a + (n-1)d
please reply. points will be given for sure.give the correct answer with proper explained solution.
the solution is: i have found the solution. please explian me the soltuion alone.
Sm=441=21^2=Sum of first 21 odd numbers(Sum of first n odd numbers is n^2).Also Sn= 256=Sum of first 16 odd numbers.So Tm=(2*21)-1=41 and Tn=(2*16)-1=31.So the answer is 41:31
just clarify me. how tn and tm are being found? please. what formulae is used here?