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Catalogs Discussion Forums -> Integral Calculus -> integrate sec(3x)sec(5x)sec(8x) -> Go to message
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sec(3x)sec(5x)sec(8x)dx

Catalogs Discussion Forums -> Integral Calculus -> e^x -1 /e^x +1 -> Go to message
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break it as e^x/e^x+1 - 1/e^x+1 now in the first integral let e^x-1=z and in the second integral multiply numerator and denominator by e^-x and then let 1-e^-x=t and answer follows
Catalogs Discussion Forums -> Integral Calculus -> dx/(a+bcosx)^2 -> Go to message
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integrate if u can

 
 
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