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 Sarvpriye Soni's messages in the community 1 2 GO Go to Page...
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 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

I think u shud do ARIHANT DIFFERENTIAL CALCULUS, it is good for present day level of JEE

 Discussion Forums -> This Post 7 points    (1    in 2 votes )   [?]

Just Apply the L-Hospital rule twice

by applying it once, u get

Limx-> 0( - (m+2) sin(m+2)x  + msinx)/ (- (m+4)sin(m+4)x + (m+2) sin(m+2)x )

again applying L-Hospital,

Limx-> 0(-(m+2)2cos(m+2)x + m2cosmx )/ ( -(m+4)2cos(m+4)x + (m+2)2cos(m+2)x)

Putting limits, we get

(m2 - (m+2)2)/( (m+2)2 - (m+4)2 )

=>  (m+1)/ ( m+3)

Rate me..........

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

wats ur problem.....................

 Discussion Forums -> This Post 5 points    (1    in 1 votes )   [?]

(99)100 > (100)99

Because,

(100)99 = (99+1)99

= 99C0 (99)99 + 99C1(99)98 + ....................... + 1

= (99)99 + (99).(99)98 +............... + 1

= 2.(99)99 + terms relatively much smaller terms

and this is much smaller than 99.(99)99 i.e (99)100

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

You willl top JEE

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

is it 29 i.e 512....................

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

In BITSAT there are 150 ques. P-40, C-40, M-45, Eng& logical-25,

Each ques is of three marks

but if u attempt all ( without leaving any), you will be given 12 additional ques. if time permits,

means u can score even 486 out of 450, 36 are bonus..........

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

In this

f(x) = 1+ 2x2 + 22x4 +.................... + 210x20

f1(x) = 4x + 4.22x3 +................+ 20.210x19

= x(4 +4.22x2 + ...............+ 20.210x19)

for f1(x)=0

either x=0

or

4 + 4.22x2 +.................. + 20.210x19 =0,

This equation has all terms with even powers of x and also all coff. are positive, thats why it has all imaginary roots.

therefore, there is only one val x=0 for which there may be max or min,

Now, at x=0 F2(x)= 4,

that's why there is only one minima..........

 Discussion Forums -> This Post 12 points    (2    in 3 votes )   [?]
Solution is simple:
e2x-3ydx + e2y-3x dy =0
(e2xdx)/(e3y) = - (e2ydy)/(e3x)

e5xdx= - e5ydy
integrating both sides, we get
e5x/5 + e5y/5 = K
(k is any constant)
or simply
e5x + e5y = C
(C=5K)

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Total Energy (U)
U=(nf/2)*RT
f for polyatomic ideal gas at room temp. is 6
i.e.
U=3nRT.
Where R is universal gas constant.
T is the temp.
n is no. of moles of that gas.
At higher temp, f=8
 This Post 0 points    (0    in 0 votes )   [?]
gud work,
thanx
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
f(x)= (2x-)3 - cosx +2x,
g(x)= f-1(x)

Find d/dx (g(x))
 Discussion Forums -> This Post 2 points    (0    in 1 votes )   [?]
Just try to grasp the concept visually, Vectors need clear understanding, For the beginning you can do it from any elementary book, then try Arihant or TMH.

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Let f(x) be differentiable function x  R. then which is true:

a) d2y/ dx2   _ (dx/dy)3 = 0
b) d2y/dx2 + (dy/dx)3.d2x/dy2 = 0
c) d2y/dx2  (dy/dx)3 = 0
d) None of these.
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Particle of charge q is brought from A to B, following the path as a sinusoidal function, and then find the work done in doing so? The point ?A?, is ?r?, distance from the infinitely long linear body having Q charge uniformly distributed on it
Write with the correct explanation for the answer.

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Particle of charge q is brought from A to B, following the path as a sinusoidal function, and then find the work done in doing so? The point ?A?, is ?r?, distance from the infinitely long linear body given in figure.Write with the correct explanation for the answer.
Please find the figure in the attached file.

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Particle of charge q is brought from A to B, following the path as a sinusoidal function, and then find the work done in doing so? The point ?A?, is ?r?, distance from the infinitely long linear body given in figure.
Write with the correct explanation for the answer.

Please find the figure is in the attached file.

 This Post 0 points    (0    in 0 votes )   [?]
it was very nice of you
 This Post 0 points    (0    in 0 votes )   [?]
Its a great thing thanks for sharing it.
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Don't waste your nickels in stupid NCERT questions.

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