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Hari Shankar   Hari Shankar is offline Hari Shankar's messages in the community
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Catalogs Discussion Forums -> Algebra -> System of equations -> Go to message
This Post 0 points    (0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]

Catalogs Discussion Forums -> Algebra -> System of equations -> Go to message
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Catalogs Discussion Forums -> Algebra -> System of equations -> Go to message
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Catalogs Discussion Forums -> Algebra -> System of equations -> Go to message
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Catalogs Discussion Forums -> Algebra -> System of equations -> Go to message
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 Are x,y,z real?
Catalogs Discussion Forums -> Algebra -> arithmetic progression -> Go to message
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Catalogs Discussion Forums -> Algebra -> theory of equations -> Go to message
This Post 5 points    (1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]

For one, AM-GM is valid for +ve reals. Here a,b,c can be any real numbers.

Catalogs Discussion Forums -> Algebra -> Pease solve this equation -> Go to message
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Catalogs Discussion Forums -> Algebra -> theory of equations -> Go to message
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Catalogs Discussion Forums -> Algebra -> theory of equations -> Go to message
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Method 1:
Catalogs Discussion Forums -> Algebra -> Quadratic equation...plzzz help -> Go to message
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Catalogs Discussion Forums -> Algebra -> Eqality -> Go to message
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Catalogs Discussion Forums -> Algebra -> Help needed in a question of complex numbers -> Go to message
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Catalogs Discussion Forums -> Algebra -> Help needed in a question of complex numbers -> Go to message
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Catalogs Discussion Forums -> Algebra -> number theory -> Go to message
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Catalogs Discussion Forums -> Differential Calculus -> limit of sequence -> Go to message
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Catalogs Discussion Forums -> Algebra -> solve this quadratic equation..plzzz help me.. -> Go to message
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Catalogs Discussion Forums -> Algebra -> solve this quadratic equation..plzzz help me.. -> Go to message
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Catalogs Discussion Forums -> Algebra -> Permutation Combination -> Go to message
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 Thank you jagdish for the appreciation.
Catalogs Discussion Forums -> Algebra -> Permutation Combination -> Go to message
This Post 10 points    (2 Olaaa!! Perrrfect answer.   in 2 votes )   [?]

Its easy to see that (y+z) is even. Hence let (y+z) = 2t.

The given equation is then x+t=10 which has 9 solutions one for each value of t, .

It easy to see that for each t, we have to solve y+z = 2t, which will have 2t-1 solutions.

Hence the total number of solutions = 1+3+5+...+17 = 92 = 81.
 
 
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