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if i'm not wrong i think its the state rank which matters more than national rank for getting admission to nit's...................each state has 50 % seats for its own state nd rest 50% for all other states..........so if u r frm assam or sumwhere where there is no competion nd u got national rank 20000 but st rank in top ten......u can get to surathkal,trichy...........thats where state ranks matters.......

how is daiict in comparison to nits(leaving trichy,surathkal,warangal)

i heard nd read frm sumwhere that daiict frm this yr is goin to give 50% seats to students frm gujarat

refer the link................

http://news.google.co.in/news/url?sa=t&ct=in/0-0&fp=4845841ebf23faf4&ei=F5BFSKm3BIiY6wOI-tHrAw&url=http%3A//www.gujaratglobal.com/nextSub.php%3Fid%3D4064%26cattype%3DNEWS&cid=0&usg=AFrqEzcWqWJ5gBq9Ss1ywXCyC3hMQ8cK0w

ne idea or case where the marks in the scorecard were diff from that in the net.........
i was xpecting 203 marks but am gettin only 167..........

wat rank did u get??

me too.......i was xpectin 203....but got 167..........the solutions cant be wrong to this extent.............

looks like there is some error in aieee marks.......
expected 203 getting 167......
dunno why??

fiitjje solutions uploaded check it out http://www.fiitjee.com/test/aieee08.pdf

since force between q1 and q2 is attractive nd also between q1,q3 is attractive..........opposite sign....

the charge q3 has to be placed on the negative side of x axis..........
force between q3,q1==kq1*q3/x^2
force between q1 &q2 =kq1*q2/4

F q1,q3 -Fq1,q2==7
solve it nd get the value of x

wats the answer??it is in terms if what??

ya i agree wid u..........joyfrancis.....

jus givin the method.......
in equlibrium
the weight will be balanced by the vertical component of tension..........
frm dat the value of tension can be known...........
now the force between the two charges is kq^2/r
r is 2lsin25
this shuld be equal to horizontal component of tension.....solvin value of q can be known.....

similarly the second part can be found out,,,,,,,,,

can give u the method write the fractional part as (|x-2|+[x])-[|x-2|+[x]]
now keep splitting the intervals nd integrate .........

is the ans Mmg/(4m+M)..................
write two equations 1 for angular motion nd linear motion.........

2TR=IA.........A=angular acc....of cylinder........
T=Ma/4
mg-T=ma.......
substitute the value of a frm one to another.........

ans is 1.73*10^5
each hydrogen atom has one electron..........
charge on electron is 1.6*10^-19C
moles =1.8
in 1 mole there are 6.022*10^23 atoms.........
total charge =
1.8*6.022*10^23*1.6*10^19=====1.73*10^5