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if A=ankur does right and R=ramesh does right

P(A)=1/8 P(R)=1/12

now both do same mistake P(A^R)' =1/1001 so P(A^R)=1-1/1001 = 1000/1001

so the probebility of correct answer is P(A' ^ R' )' [in ankur & ramesh any

one gets correct answer

=P(A)+P(B)-P(A^B)

=1/8+1/12-1000/1001

= -18995/24024 we will get it.we have

to find P(A' ^ R' )' ]

plz tell me the date of jee08.

hey guys plz tell me what is the date of jee08? i am not going to apper this year.i will apper next year

if you write i,j & k in traingle shape like i

k j

and moves to clockwise direction you will get

i * j = k , j * k = i,k * i =j

now if you moves anticlokwise direction

i * k = -j , k * j = -i , j * i = -k

it may be solve by critical point methord

hey redevil if it is -2007 C 2007 then you are absulitly wrong.in combination you

have to select something from the given quntity.and given quntity

is always grater then zero. so plz

check your question.

in sp3 hybridization one s and three p orbitals hybrides.if we take methyn there is sp3 hybri.in it in carban it has one unpair elecrone in s orbital which attached with three elecrones of p orbital and makes four same staringh sp3 bonds.

you cannot hit the to the rod in space in absance of gravitaional force

are you sure with the ans? i don't think so it is right.

if deector is moving in +ve x-axis direction &soruce in -ve x-axis direction

then

for both V_S&V_d=a*t=20

fs/V-Vs =(f)_d/V+V_d

so f_d=f_s(330+V_d) / 330-V_s

f_d=330+20 / 330-20

f_d=35/31 khz

i agree ramyani.but if bc is strigt then... draw tengat they will same

i didn't mantion they have same velocity.they do con acc.

and hey....

p&q both moves to each oyher as you told.

is it stright line between b &c. if it then instantteneous velocity remains same during b_c period.so instantteneous velocity is same at b &c.

if not then ans will AT B point

if they both do constant acc motion then &their acc is A

then time t=root(D / A)

for p it meet q at D/2 as they both do con acc

THEIR u=0 so from D/2=ut+1/2 At^2

D/2=1/2 At^2

t=root(D / A)

can we repeat one letter?

if we can then it will be

13! / 4!2!3! =21621600

is zero integral shoosy?