yaar first make tan into sin's and cos's.

now take L.C.M

2sin80cos50=cos40-cos120=cos40+1/2-----(1)

1/2(2cos120+cos40)=1/2(-1/2+cos40)---------(2)

sin50cos60=-1/2cos40.-----------------------------(3)

co80cos50=1/2(2cos80sin40)=(sin60-sin40)1/2--(4)

substitute

Hope u got it......

yaar by drawing free body diagram the first part can be done very easily.

T-(2g+1)=2a

5g+1-T=5a

----------------(+)

a=3(10)/7=4.3(aprox.)

for second part 5g+1=5a   (body is freely falling & 1Nforce is acting)

a=g+0.2

simple yaar resolve the wt. of 2nd body along the plane that should be equal to electrostatic force.

now caliculate for r

after simplifying for x=d/2rt2

solve it u get the answer.

on simplifying the equation given u get

(a-c)^2>=0 so a^2+c^2>=2ac similarly for 2bd.

now (ad-bc)^2>=0

substitute above statement

.But d^2+c^2>1 can`t be proved

send the f(x) terms other side

on simplification

now substitute x value

f(x)=2(1-3^1/2)

(74.2)(V)/76=(0.375)(8.314)(299)

now caliculate for V.

sinA=6/10

theta=

         ==29degrees

-------------------------------------

now solve above equations

yaar very simple

slope at (4,3)is dy/dx=-4/3.

the tangent will meet the axis at x=25/4.

length of tangent is 3root17/4.

slope of normal is 3/4,normal will meet axis at x=0.

length of normal is 5.

area is 1/2(3root17/4)(5)=15root17/8.