Bromination of ethane with bromine in presence of light or 670K to form bromoethane. Bromoethane on reaction with aq. KOH gives ethanol, which on oxidation gives ethanoic acid. Decarboxylaation of ethanoic acid with sodalime gives methane. methane in presence of molybdenum oxide with oxygen under pressure gives methanal ( formaldehyde), wich on oxidation gives formic acid ( methanoic acid)

Ethanoic acid can also be obtained by oxidation of ethane in presence of silver oxide, then again the rest of the above steps can be followed.

 Racemic mixture is mixture of 50% d and 50% l form, therefore it is optically inactive due to external compensation( half of the molecules rotate in clockwise and another  half in anticlockwise direction thus getting cancelled)

 Formalin is aquesous solution of formaldehyde

 N2O5 is viewed as two NO2 joined through O, i.e., N-O-N. NO2 is O-N=O, thus nitrogen may be regarded as sp2 hybridized.

 barium sulphate is responsilble for poisoning the surface of the catalyst preventing over reduction. If this is not done the aldehyde formed will be easily reduced to the primary alcohol.

 I have not come across such reaction, however the reaction being SN2 less hinderance in cyclopentanol as compared to cyclohexnol may be the reason.

 Carbon atom adjacent to the functional group is alpha, next beta, third gama, then delta, and so on. For example

CH3-CH2CH2COOH is Butyric acid, CH3CH2CHClCOOH IS ALPHA CHLORO, CH3CHClCH2COOH is beta chloro

 Ethane on heating with bromine gives bromoethane.

 In my humble openion concentrate on present studies, you are persuing a good course, it is better to continue. If you are sure without affecting your present studies you can appear for JEE then go ahead but not at the cost of present career.

 Slow oxidation to formic acid.

 You mean order of priority for nomenclature? It is as follows: (source NCERT book)

-COOH, -SO3H, COOR, COCl, CONH2, CN, CHO, CO, OH, NH2,C=C, C triple bond C

 Don't try to memorize the organic reactions, there are so many and its difficult to memorize all. Understand the reactions with their mechanisms by writing down the same, then you will automaticaaly remember them.

 As s electron is nearer the nucleus due to its penetrating power, electronegativity increases with the increasing s character of the hybrid orbitals. Thus the electronegativity values for carbon are  2.48, 2.75 & 3.29 for sp3, sp2 and sp state respectively.

 Yes, nearly the same.

 Please check with the concerned authorities/ contact the institute for correct guidance.

 Wurtz reaction with mixed alkyl halides(two different alkyl halides) will lead to all the possible products, for ex. reaction between CH3Br & C2H5Br with sodium metal will give CH3-CH3, C2H5-C2H5, & CH3-C2H5; hence the reaction is not suitable for preparing alkanes with odd no. of carbon atoms.

 Fluoride ion is a stronger base hence a poor leaving group, similarly CH3OH is also a poor nucleophile; hence the substitution will be very slow, where F may be replaced by CH3O-.

Elimination takes place in presence of strong base, CH3OH is not at all basic, so the question of elimination should not arise. If the reaction is with KOH in CH3OH then elimination can take place and the product will be CH3CH=CHCH3(Saytzeff rule)

 Isoppropanol CH3CHOHCH3 molar mass 60 , contains 8 hydrogen atoms.

So, 60g isopropanol contains 8g hydrogen, therefore 6g will contain 0.8g hydrogen

1g of hydrogen contains contains 6.023 x 10²³ atoms of hydrogen, therefore 0.8g of hydrogen will contain ?

(I am poor in calculations hence do the calculations to get the correct answer, if the atomic weight of hydrogen is given in the problem diffferent than 1 make necessary changes in the calculations)

 The cause of basicity is the availability of lone pair of electrons on nitrogen for protonation. In CH3CH2NH2 the lone pair is freely available. In CH3CONH2 the lone pair is involved in resonace with C=O hence not freely available for protonation thus it is not basic, however amides are amphoteric in nature ,i.e., they show both acidic and basic properties.

 Symmetrical trans alkenes are non-polar and hence have zero dipole moment since the dipole moments of individual groups being equal and opposite exactly cancel out each other.