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simple...
initial velo=u
accel=a
using s=ut+.5at^2
150=2t+2a ......... u+a=75
for second case total s=150+210=360 time =4+2=6
360=6u+18a
solve these eq to find u and a
hence find velo after 9secs....
easy...find five AMs and HMs bet 97 and 99
the am of these inserted terms will be the fourth term of the ap series (i.e 98 )starting from 97
similarly for harmonic series in which the hm of inserted terms is 97.9
ans b.[1,infinity)
do hafte rook jaaa result aaa jayega ....waise no key is available since paper was not handed over after exam...to key kahan se aaa jayegi ...
kisi ko pata hai papers kahan mil sakte hain??????????
how you calculated your marks dude....
well at 650 you may get between 500 -1000
sorry dude no hopes
score is too low..
102
how many allternatives question has.
i dont think so ... u cant rely fully on it since problems in their module are not of that much level as asked in jee.
well it should not be acceleration but deacceleration...
5.....well its a biquadratic equation and it can be solved as follows
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