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well ok....................got the ans......thank you all
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but i think i too made a mistake.........becoz im not getting the right ans that way
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yeah u r right.....made a silly mistake .............
thank you everyone
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Nitrogen can rarely form allotropes
Unstable allotropes of nitrogen consisting of more than two nitrogen atoms have been produced in the laboratory, like N3 and
like Hexazine composed of 6 nitrogen atoms similar to benzene in shape
N6
But it is highly unstable and explosive at room temperatures due to its decomposition reaction
N6 -> 3N2 + heat
Hence is unstable and dosent exist
And also the triple bond in molecular nitrogen (N2) is one of the strongest in nature , this results in difficulty of converting (N2) into other compounds,
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one point is (1/m-n , m/m-n)
other is (1/m-n , n/m-n)
but not getting the other two :(
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Find the area bounded by the lines
y=mx,
y=mx+1
y=nx
y=nx+1
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very useful ................thanx a lottttt........
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prathima, observe the diagram
one of the p orbitals overlap by end on overlap and form sigma bond
the remaining p orbitals form pie bond by side on overlap. Thus there is no orbital left to form another pie bond.
The p orbital indicated by blue colour cant overlap with the orbital shown with yellow colour. Hence C4 bond is not possible.
Whereas the blue coloured orbital can overlap with the orbital of an other atom, shown with red colour
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