inert pair effect is the non-participation of the s-electrons in the bulkier atoms.

the s-electrons don't participate due to poor sheilding effect of the f orbitals.

therefore they can't be lost very easily. if they're lost they destabilize the atom

occurs in heavy elements like Pb, Bi , Tl etc.

ex in Bi

+1 oxidation state is more stable than in +3

stability order of +1 state in grp 15

Bi>Sb>As

reverse for stability of +3

rate me if all this helps me.......

yup

tis CaC2

142

damn sure

rate me if u think tis crct.

1st solve 2nd and 3rd term by Sin C + SinD

u'll get sin (2a+360)/2 left

then add it to sin a by solving the angles

u'll get cos90 on solving multiplied by some term.

pardon me,

it is 142 avagdro no.

ughhh...

typing dis one is a diffcult job.

but the soln is:

find the coordinates.

u'll get relations b/w a and b  by equating the sides

and u can form another eqn by proving that the diagonals intersect perpendicularly.

hence get the answer

the formula is:

x'=x1-2aL1/a square plus b square

x1= coordinates of d point

ax+by+c is the eqn of the line

and L is no. which u get after putting the coordinates in the eqn of line

no u're wrong bcoz if R is any functional grp containing Carbon then 1st priority will be given to it...

and the name will completely change.

The alkanes having a straight or normal chain are called normal or n- hydrocarbons.

The alkanes in which the carbon chain has branches are called branched chain hydrocarbons. Such alkanes as possess a one-carbon branch on the 2nd carbon of the normal basic chain, are called Iso hydrocarbons.

When the normal carbon chainpresent in the molecule has 2 one-carbon branches on the 2nd carbon from the end, the alkane is referred to as Neo hydrocarbon.

Secondary or 2degree carbon atom is the one which is bonded to 2 other carbon atoms.

Tertiary or 3 degree carbon atom is the one which is bonded to 3 other carbon atoms.