Messages posted by Sagar Saxena

vertices are:

diferentiate,find tha value of x at which dy/dx = 0

x = -3 / 4a

y = -35 a / 16

eliminate a

xy = 105 / 64

hello dear..

u have ill the online form ,and send them a DD to their offcice.....

plz refer this website:

http://www.bitsadmission.com/

hello dear..

to find the minimum distance between two curve..

let us assi=ume some value of (a),without some value of (a),v cant find the minimum distance netween the curves.........

if thw two curves intersect,it means the curve have real value of x and y......the minimum distance is zero.....

if the curve dont intersect than>>

find the point on the curve which are at minimum distance with each other......

plz,give me some question,so that i can clearly illustrate this concept

on homogenizing two equations:

y² = 4a x (lx+my) / -n

n y² + 4al x² + 4am xy = 0

two lines to be perpendicular:

n + 4al = 0

well dude..

iam writing the answer for this.plz confirm it:

= 1/ 2^1/2 [tan^-1(t - 1/t) / 2^1/2 + 1/2 log ( t + 1 / t - 2^1/2) / ( t + 1/ t + 2^1/2) ] + c

where t = (tan x)^1/2

dude,

this non integrable function till the methods used which prescribed in IITJEE syalbus.....well,u read more methods of integration in engg.........

few non integrable functions in IITJEE course are:

sinx / x

cos x / x

e^x^{^2}

e^-x^{^2}

cos x²

x tan x

root of(sin x)

many more........

this is one of the integral which cant be solved

few more integrals of this types are:

1. Sin x / x

2. 1 / log x

3. cos x / x

4.etc.....

hello dear..

Conis method in complex number is also called a rotation method in it..

let the three point be:

Z₁ , Z_{2 ,}Z₃

A , B ,C

angle between AB and AC is

arg [(Z₂ - Z₁) / (Z₃ - Z₁)]

read more explaiantaion from AD gupta

well dude,in empty space photon travels at s peed of light..well,its velocity depend upon the freequency of the source......its energy and momentum are related by E = pc

if 4 is the option than it implies all the options.....no doubt

hell0o dear

A + B + C = 180⁰

A + B = 180 - C

TAKING TAN ANGLE ON BOTH THE SIDES

tan (A+B) = -tan (C)

tan A + tan B / (1-tan A tan B) = -tan C

tan A + tan B + tan C = tan A tan B tan C

where A,B,C are the angles of atriangle.........

if u want to ask something other than this..plzplz nudge me

i think sir,they want a proof of cosine law from the projection rule.........u have separtely prove both

hello dear.......

i dont think so,that thr is any controversy in mathematics............plz restate the question,what u want to ask

if controversy is related to toughnes of the subjectthan sorry ,no expert can help u in this regard

yes dude......correspondance course is available for pre claases such as 9th and 10th.......Brilliant tutorials provide correspondance package for the preparation of IITJEE

hello dear..

The answer is (4)

the sweetest and the simplest approach of this is ,start puting the options.........start with 4th option bcz all the three x,y,z are given in this option

hello dear..

the equation can be written as :

(x+1)² / 12 - (y-2)² / 16 = 1

x = -1 + 12^1/2 sec x

y = 2 + 4 tan x

false dude..........

any point point on hyperbola is :

(5sec (theta), 4 tan (theta))

dude.......

give me some example of it,so that i can clearly illustrate u the concept

hello dear..

quite simple appliucation of binomial; thoerem..

the gerenral coeficient is : C (n,r)

here three consecutive coefficients are:

C (n,r) = a (1)

C (n,r+1) = b (2)

C (n,r+2) = c (3)

(r+1) / (n-r) = a/b

and

(r+2) / (n-r-1) = b/ c

solve for n =( 2ac+ba+bc ) / (b.b-ac)

What is 1+Logm base n =

log _n m + 1 =

log _n m + log _n n

log _n mn

whats in this question dude...........what more u want to ask ,plz clearifies it more and nudge me

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