H+ concentration is equal to 0.001 molar

When you shoot a bullet on a glass, the glass doesnt break.... theres just a hole created in it. But if you shoot a bullet on a stone, then the stone crumbles. Why ?

When you shoot a glass with a bullet, the bullet just penetrates through without breaking the glass. However, when you throw a stone, the glass breaks completely. Why ??

im sorry the answer is (n^2)/2 + n/6

I guess den what the problem means is ....

Find the angle beyond which there will be no refraction .... den in dat case u can't take any angled prism .... but the language of the problem is yet pretty unclear !

Yes exactly even i was getting 1.

But answer in fiitjee booklets e^(1/2)

Well i havent missed anything in the problem.

And u can't take a prism of any angle !

This is the problem as it was in objective physics in D.C. pandey.

And i dont want a method to get 60 degrees . i want to know the concept behind the problem .

Well i havent missed anything in the problem.

And u can't take a prism of any angle !

This is the problem as it was in objective physics in D.C. pandey.

And i dont want a method to get 60 degrees . i want to know the concept behind the problem .

where {.} denotes fractional part of x .

And ^ means raised to.

Ans: e^(1/2)

ya sorry i did now .... the small box is actually 'd' for dx

where {.} denotes the fractional part of x.

Ans. ( (n^2)/2 - n/6)

The refracting index of a prism is 2. What is the maximum refracting angle of the prism

(ans: 60 degrees)

Exactly which formula does one learn to count the lone pairs ?!? .....

Its better to draw the structure and use hybridisation theory to get the lone pairs.

H₂O can be regarded as a strong field ligand.

The Strength goes as follows

I^-<Br^-<SCN^-<Cl^-<F^-<OH^-<C₂O₄^2-<H₂O<edta^4-<NH₃<CN^-<CO

:)

This is beacuse we cannot just add the emf values directly . We have to add the Gibbs Free Energy and then calculate standard potentials indirectly. This is beacuse the Gibbs Free Energy of the resulting rxn is equal to the sum of the Gibbs Free Energy of the first two reactions. (By basic definition of enthalpy).

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PLEASE RATE IF USEFUL ! :)

The solution is as follows...

SCl₂ + 2C₂H₄ ------- S(CH₂CH₂Cl)₂

At t=0 0.5M 1M 0M

At t=t_eqb 0.5-x 1-2x x

Now x is given as 0.3 = [S(CH₂CH₂Cl)₂]

Therefore concentration of SCl₂ = 0.5-x = 0.2 = [SCl₂]

And concentration of C₂H₄ = 1-0.6 = 0.4 = [C₂H₄]

Equilibrium constant K of this reaction is given by

[S(CH₂CH₂Cl)₂]

[SCl₂] X [C₂H₄]²

Putting values u get Keqb as 9.375

PLEASE RATE IF USEFUL ! :)

Thats a nice question.

For f(1) when u substitute p as 1 and then find out the first few terms u will get 1- 1/2! + 1/3! - 1/4! .....

which is nothing but e-1/e ....

The same can be done for the rest of the questions ....

Please nudge me if u want a detailed answer ...

PLEASE RATE IF USEFUL !! :)

Im sorry sagar but thats wrong .... matrix multiplication doesnt follow that law.

And 'aatman' the options and the answer both are wrong.

There is a property in trace for three matrices that is the order of a matrix is changed without changing the position of the individual matrices with respect to each other the trace of a matrix remains unchanged.

What i mean is trace(ABC) = trace(CAB)= trace (BCA) .... im not interchangin any 2 positions here .... im just advancing the cycle of the matrix like we do in scalar triple product of vectors.

So here you can also verify that u wont get any of your options by substituting any 3 non singular matrices and u will find out that only Trace(ABC) = Trace (CAB) = Trace (BCA).

..

if im unclear nudge me ....

PLEASE RATE IF USEFUL !

do it mechanistically.

Know the correct mechanism of whats happenin in the rxn ..... whether its oxidation or reduction or disproportionation .... etc ...

And make ur own codes for certain rxns whose mechanisms are difficult ... Learning reactions this way could really be fun !

Mol wt of nitric acid = 63

Therefore no of moles of acid = 0.063/63 = 0.001

Since no concentration is mentioned I am assuming it is in 1 liter solution.

Thus concentration of nitric acid = 0.001 molar

HNO₃ = H⁺+ NO₃^-

Since it’s a strong acid taking degree of dissociation 1.

H+ concentration is equal to 0.001 molar

Thus OH- conc. is equal to Kw/ H⁺

Where K_w is dissociation constant of water = 10^ (-14)

Therefore OH- conc. = 10^(-11)

(please rate if useful)HHhh

Molecular mass is M itself .

I₂ + F₂ = IF

So here Iodine’s valency has gone from 0 to +1. Thus there is 1 electron change. However valency factor is defined as change in oxidation no. per atom .

Here change per atom is ½

Thus equivalent wt of iodine = mol.wt./ valency factor = 2M

H+ concentration is equal to 0.001 molar

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