Messages posted by coolsentosa

is the above latex visible?

5 is least stable because it is triply vinylic (there is no hyperconjugation). next is 3 because it is single vinylic (there are two hyperconjugative H) next is 1 because there is no resonance, it is simple radical (with 4 Hyper- H) then is 2 and most stable 4 (because of single conjuagation and triple conjugation respectively)

latex

it was der before also

For ALL halogens their -I effect is much more than their +M effect.. (All halogens without exception) . But the acidity decreases in the order -I>-Br>-Cl>-F because of more stability of +M of F .... btw IIT did NOT give the answer as the first compound.. The book did.... U never know who is correct

i need more help

i beg to differ sir. But what asish hsa said is correct. This is because the relation is transitive if (a,b) and (b,c) belong to the relation then (a,c) should belong to the relation. If the hypothesis itself is false, then the conclusion must be true. This is the general result for the truth table for implication which states that p-->q is false if p is true while q is false otherwise it is true . As the hypothesis itself is false i.e. (a,b)(b,c) do not exist. hence the implication must be true hence the relation is transitive (trivially)

can someone explain me the concept of waves. I have read HCV & Resnick but in vain

i think it wont.

its (b)

Suppose you have a circular portion cut out from a disc such that it touches the rim H C Verma Pg 160 Q5.

Here COM = MR - (m)r/M-m

i.e the cut out portion can be treated to have negative mass.

Rate if useful or nudge for more information

obviously u realise that it is a 3-d problem. There is 40 N force which pushes blosk towards wall and the 15N force pushes it in horizontal direction. Try using a book or a block to visualise it. So the friction will not only balance the weight but also the 15N force.

iiittt ur answer is correct but look at the options given carefully

experts please help

A ball of mass m is given an initial rotation w as shown and allowed to fall from a height h on a rough plate of mass M which rests on a smooth surface.The friction coefficient between the ball and the plate is μand the coefficient of restitution is e..Now it rebounds and continues to move in air.

.

Then answer the following questions.

After rebound the trajectory followed by the ball and the centre of mass of ball and plate as a system will be ,

a) parabola and straightline respectively.

b) parabola for both.

c) straight line for both.

d) can't be determined.

Q42) In the previous question,

What is the impulse delivered friction on the ball when it rebounds ?

a) μem√(2gh)

b) μ(e-1)m√(2gh)

c) μ(e+1)m√(2gh)

d) (μm/e)√(2gh)

Q43) What is the velocity acquired by the plate immediately after rebounce of the ball?

a) μM√(2gh)

b) (μm/M)(e+1)√(2gh)

c) μMe√(2gh)

d) μM(e+1)√(2gh)

Q44) What is the range of the ball with respect to the plate.(In other words find the distance on the plate where the ball lands again).

a) 2heμm/M

b) 4h(e+1)μ(1+m/M)

c) 4he(e+1)μ(1+m/M)

d) 2h(e+1)μ(1+m/M)

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