Messages posted by deraj_pv

hi! plz....give a list of books for iit and aieee for my study.....which consists of both concepts and a good no. of problems.i wish all the iit examiners "all the best".

hi! plz....give a list of books for iit and aieee for my study.....which consists of both concepts and a good no. of problems.i wish all the iit examiners "all the best".

yes. infinity + anything = infinity
here, infinity + sin720=
sin720 = 0
therefore infinity + 0 = infinity
u need not see the term that follows infinity in addition and subtraction.

hope it is clear.

infinity

yes i agree with umesh

i can say u some more...

MATHS
1) Higher Algebra - Hall & Knight
2) Trignometry - S L Loney
3) Coordinate Geometry - S L Loney
4) Calculus - Thommas & Finney
5) IIT-JEE Maths- TMH

PHYSICS
1) Universtiy Physics ( Freedman and Young) - This book is required to clear the concepts.
2) Concepts in Physics I & II (H.C. Verma)
3) General Problem in Physics (I.E. IRODOV)

CHEMISTRY
Physical Chemistry
1) Problems in Chemistry - R.C. Mukherjee
2) Macmurry Fay

Organic Chemistry
1) Organic Chemistry - Solomon

Inorganic Chemistry
1) Concepts of Inorganic Chemistry - J.D. LEE
2) Inorganic Chemistry - O.P. Tandon

please reply soon

please reply soon

i know that it is an isosceles triangle ......i want the solution

if in a triangle ABC, c(a+b)cos(B/2) = b(c+a)cos(C/2) then the triangle is.......

plz...give a solution as soon as possible.

In a triangle ABC, If the incircle passes through the circumcentre of the triangle ....then find the value of cosA + cosB + cosC....

plz....give me a solution for this....

thank u every much for solving my answer

i have changed the question .....plz...answer my question

hi vaibhav....ur question is
in a triangle ABC,D,E are the points on B,C suchthat BD=DE=EC IF

BAD=

X

DAE=Y

EAC=Z SHOW THAT SIN{X+Y}SIN{Y+Z}/SINXSINZ=4

This is a easy one ..u have to just understand wat is given
the solution is
consider angle BDA = q and angle BEA= w

from triangle BAE,

2a/sin(x+y) = c/sinw.............(1)

from triangle BAD,

a/3sinx=c/sinq    .............(2)

now,eqn.(2)/(1)

a/sinx.3sin(x+y)/2a = c/sinq .sin(w)/c

         sin(x+y)/2sinx=sinw/sinq ...........(3)

from triangle DAC,

2a/3sin(y+z)=b/sinq

from triangle EAC,

          a/3sinz=b/sinw

sin(y+z)/2sinz=sinq/sinw.......(4)

therefore,from (3)X(4) we get

sin(x+y)sin(y+z)/sinxsinz = 4

The solution is-
put x= sin(z) and y= sin(q)

z=sin^-1x and q=sin^-1y

(1- sin²z) +

(1- sin²q) = a(sinz - sinq)

                       cosz+cosq = a(sinz - sinq)

2cos(z+q/2)cos(z-q/2) = 2acos(z+q/2)sin(z-q/2)

cos(z-q/2)/sin(z-q/2) = a = cot(z-q/2)

                      (z-q/2)=cot^-1 a

                           z-q = 2cot^-1(a)

         sin^-1x -sin^-1y = 2cot^ -1(a)

                diff. w.r.t."x"

1/

(1-x^2) - 1/

(1-y^2) dy/dx = 0

1/

( 1-y^2) dy/dx = 1/

( 1-x^2)

dy/dx =

(1-y^2)/

(1-x^2)

Hence proved

i hope u r satisfied now.

plz...express ur question clearly using the tools.

hi!
can u send any iit model paper for practice to deraj_pv@yahoo.co.in

i can tell u one .....ie...problems plus in iit mathematics

hi!
my question is

If the lengths of sides of a,b,c of a triangle satisfy
2(bc²+ca²+ab²)=b² c+c²a+a²b+3abc ......then the triangle is a............?

please send me the solution.

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