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 Solution :
The wire would also act as an spring whose spring constant will be YA/L.
There are two springs in the series.
Hence the equivalent spring constant is given by
(1/knet) = (1/kwire) + (1/kspring)
= (L/YA) + (1/kspring)
Time period = 2  m/knet
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Any chemical bond results from the accumulation of charge density in the binding region to an extent sufficient to balance the forces of repulsion. Ionic and covalent binding represent the two possible extremes of reaching this state of electrostatic equilibrium and there is a complete spectrum of bond densities lying between these two extremes. Since covalent and ionic charge distributions exhibit radically different chemical and physical properties, it is important, if we are to understand and predict the bulk properties of matter, to know which of the two extremes of binding a given molecule most closely approximates.
The dipole moment is defined as the product of the total amount of positive or negative charge and the distance between their centroids
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Sorry by mistake i posted the solution here.
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Any chemical bond results from the accumulation of charge density in the binding region to an extent sufficient to balance the forces of repulsion. Ionic and covalent binding represent the two possible extremes of reaching this state of electrostatic equilibrium and there is a complete spectrum of bond densities lying between these two extremes. Since covalent and ionic charge distributions exhibit radically different chemical and physical properties, it is important, if we are to understand and predict the bulk properties of matter, to know which of the two extremes of binding a given molecule most closely approximates.
The dipole moment is defined as the product of the total amount of positive or negative charge and the distance between their centroids
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Amaron has done a great job.
Since it is an objective problem, consider it as an eqilateral triangle.
Then a=b=c and the expression becomes 0.
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Because in ammonia, nitrogen atom is central.
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Preferably you should give the exams at an early date.
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Hey dear dont worry yaar...........
Fluctuations are always there in different tests but this doen't mean that you are going down.Just see the papers in which u have got less marks.Pick the questions from your strong topics and just see where u have missed some concept and think over those concepts.I mean to say give some time over those papers.
If your concepts are good then you wil definitely go through.
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Kiran has explained it perfectly.
Due to incident ultraviolet rays and their interaction with oxygen ozone is formed and after that it destroys thereby absorbing the harmful radiations.Due to their continuos creation and destruction they remain in stratosphere even when it is heavire than oxygen.
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You are most welcome to IIT.
Best of Luck.
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Its IUPAC name is Diaminomethanal.
It is also known as carbamide.
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In case of CH2Br2 elctron donating group increses electron density on carbon atom and hence carbon attracts hydrogen atoms towards it.Hence bond length is higher for C2H4.
We are instructed to answer one query at a time.So please post your other queries on a new page.Hope you understand.
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The van 't Hoff factor i is the number of moles of solute actually in solution per mole of solid solute added. Equivalently, i refers to the ratio of true molecular mass to calculated molecular methods by colligative methods.
When solute particles associate in solution, i < 1.
Degree of dissociation  = (i - 1)/(n - 1)
When solute particles dissociate in solution, i > 1.
Degree of dissociation = [i - 1]/[(1/n) - 1]
Otherwise i = 1. = 0
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Actually cut-off marks vary from paper to paper and after the level of paper and according to no. of seats cut-off marks are decided by JEE cell.
You should not worry for cut-off marks, if your preparations are good then you would definitely qualify JEE.
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[x2-] = -4 0<=x<(-3)
= -3  (-3)<=x<(-2)
= -2 (-2)<=x<(-1)
= -1 (-1)<=x<
= 0 <=x<(+1)
= 1 (+1)<=x<(+2)
= 2 (+2)<=x<(+3)
= 3 (+3)<=x<(+4)
= 4 (+4)<=x<(+5)
= 5 (+5)<=x<(+6)
= 6 (+6)<=x<
Hence integrating x.sin[x2-] in the above intervals sin[x2-] becomes constant and we are left to integrate x .
After simplifying the integral comes out to be
I = [(4-)/2].sin4 + (sin5)/2 + [(2--6)/2].sin6
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Rao Prabhat is exactly right.
In case of mixture of gases Dalton's law of partial pressure should be applied.
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Frequency deviation (?f) is used in FM radio to describe the maximum instantaneous difference between an FM modulated carrier frequency, and the nominal carrier frequency. The term is sometimes mistakenly used as synonymous with frequency drift, which is an unintended offset of an oscillator from its nominal frequency.
The frequency deviation of a radio is of particular importantance in relation to bandwidth, because less deviation means that more channels can fit into the same amount of frequency spectrum. The FM broadcasting range (88-108 MHz) uses a channel spacing of 200 kHz, with a maximum frequency deviation of 75 kHz, leaving a 25 kHz buffer above and below the center frequency to reduce interaction with other channels AM broadcasting uses a channel spacing of 10 kHz, but with Amplitude modulation frequency deviation is irrelevant.
FM applications use peak deviations of 75 kHz (200 kHz spacing), 5 kHz (25 kHz spacing), 2.25 kHz (12.5 kHz spacing), and 2 kHz (8.33 kHz spacing).
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Arvind is correct.
Alternative way :
Flux =  B.dA
[Flux] = [BA]
= [EA/v]
= [VA/vL]
= volt-sec
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For latest news refer to the link
http://www.indiaedunews.net/IIT/IIT_Kharagpur_ready_to_roll_out_reservation_plan_62/
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For derivation refer to the link
http://www.chem.arizona.edu/~salzmanr/480a/480ants/gibshelm/gibshelm.html
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