Bipin Dubey   Bipin Dubey is offline Bipin Dubey's messages in the community
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Catalogs Discussion Forums -> Electricity -> help needed !!!! -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Just go step by step

1st find out the charges on capacitors, comes out to be
Q1 = CV   and   Q2 = 2CV

After dielectric is introduced new capacitances are kC and 2kC.
Let the charges on them be Q1' and Q2'

Since they are connected in parallel equate their P.D.
Q1'/kC = Q2'/2kC
gives  Q1' = 2Q2'

Charge conservation gives
Q1' + Q2' = Q1 + Q2 = 3CV

These two equations give Q1' = CV   and   Q2' = 2CV

Hence V1 = V/k   and   V2 = V/k

Catalogs Discussion Forums -> About IITs and JEE -> pattern of jee -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
You can expect anything from JEE.

But I think that the two papers would have same weightage.
Catalogs Discussion Forums -> Trignometry -> triangles -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Amaron has done it nicely.
Catalogs Discussion Forums -> Integral Calculus -> clarification -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Yes kiran is right. Expand the denominator and carry on.
Catalogs Discussion Forums -> Algebra -> probability -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
P(A B) = P(A) + P(B) - P(A B) = 0.54 + 0.69 - 0.35 = 0.88

P(A' B') = P(A B)' = 1 - 0.88 = 0.12

P(A' B) = P(A) - P(A B) = 0.54 - 0.35 = 0.19

P(A B') = P(B) - P(A B) = 0.69 - 0.35 = 0.34


Catalogs Discussion Forums -> Thermal Physics -> thermodymanics -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
But what to do in the question?
Catalogs Discussion Forums -> Electricity -> about electric field -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
To help visualize how a charge, or a collection of charges, influences the region around it, the concept of an electric field is used. The electric field E is analogous to g, which we called the acceleration due to gravity but which is really the gravitational field. Everything we learned about gravity, and how masses respond to gravitational forces, can help us understand how electric charges respond to electric forces.
The electric field a distance r away from a point charge Q is given by:
Electric field from a point charge : E = k Q / r2
The electric field from a positive charge points away from the charge; the electric field from a negative charge points toward the charge. Like the electric force, the electric field E is a vector. If the electric field at a particular point is known, the force a charge q experiences when it is placed at that point is given by :
F = qE
If q is positive, the force is in the same direction as the field; if q is negative, the force is in the opposite direction as the field.
Catalogs Discussion Forums -> Analytical Geometry -> points and straight lines -> Go to message
This Post 2 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
Compare it with ax2+2hxy+by2+2gx+2fy+c=0

Put the values in
tan-1[2(h2-ab)1/2]/(a+b)

You will get
/2.
Catalogs Discussion Forums -> Differential Calculus -> limits -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
As x tends to -1 it would not be in the domain of sin-1x.
Hence the limit does not exists.
Catalogs Discussion Forums -> Thermal Physics -> latent heat -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
As we increase pressure the molecules come closer and closer and the potential energies of interactions between the molecules contribute to its heat capacity.Hence latent heat is reduced.
Catalogs Discussion Forums -> Counselling Zone -> hi -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
You follow the link :

http://www.ige-india.com/WELCOME.html
Catalogs Discussion Forums -> Mechanics -> elastomers -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
You may also follow the link :

http://www.pslc.ws/mactest/elas.htm
Catalogs Discussion Forums -> Trignometry -> mathametics -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
As you practice more and more, your mind will be set for exams and u can easily crack aieee.
Catalogs Discussion Forums -> Organic Chemistry -> REVISION -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Study your notes thoroughly specially in inorganic and do make a shedule and stick to it.Give more time in learning mechanisms.
Morning is the best time to grasp things, so you should flick through your pages every morning.
Catalogs Discussion Forums -> Physical Chemistry -> volumetric analysis -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Apply N1V1 = N2V2

Basicity of citric acid is 4.
Acidity of Ba(OH)2 is 2.

Hence
(4)(25)(M) = (2)(31.65)(0.165)

M = .104445


Catalogs Discussion Forums -> About IITs and JEE -> syllabus -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Surely dear u must study them in detail, without them coordinate geometry would be tasteless.
Catalogs Discussion Forums -> Thermal Physics -> thermo -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Using C = R/(-1) + R/(1-x)

answer comes out to be b).
Catalogs Discussion Forums -> About IITs and JEE -> General- iit_jee -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
There is no screening exam,u you have to just clear the mains and u will be through.It includes physics,chemistry and maths.
Catalogs Discussion Forums -> Analytical Geometry -> hyperbola question -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
I have shifted the origin so as to make the equation of the curve to be convenient in the form of xy = constant.
Catalogs Discussion Forums -> Non IIT Institutes -> admission in IIScs and other indian institutes. -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
It offers postgraduate and doctoral research programmes to over 2,000 active researchers working in 48 specialized departments.
It does not offer undergraduate course.
 
 
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