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my iit rank is E23439,how can i apply for various colleges that take admission by iit eml
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orthogonal trajectories of family of parabolas y^2=4a(x+a),where 'a' is an arbitrary constant is:?ans is y=ce^(-x/2a), where c is a constant.please give me complete explanation.
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please note question correctly :
integration of : root of {tan^2 (x) +2};
your ans is wrong
please give me correct as with explanation
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sorry,please give whole solution
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thanks ;lets try the other problems by me ;
& same to you for exams;
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my friend , i have already tried this method but i got wrong answer ;
the corrrect answer is :1/6 log |1-cos x|-0.5 log |1+cos x|+1/3 log|2+cos x|;
so please give me whole solution;
so that i will point for you
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integration of (sin^8 x - cos^8 x)/(1-2sin^2 (x) cos^2 (x)). Please give whole solution
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integration of 1/cos x-sin x) please give whole solution
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integration of {(root of cot x) - (root of tan x)} / (1+3sin2x)
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integration of (root of cot x) - (root of tan x) / 1+3sin2x
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integration of : 1/(1+root of cot x)
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integration of log(cos x +root of cos2x) /sin^2 x
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integration of (cos^2 x) /1+tan x
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integration of {x/(x sin x+cos x)}^2
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integration of root of {sin(x-a)/sin(x+a)}
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integration of root of (tan^2 x+2)
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integration of 1/{sin x(2+cos x)}
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Vriti Edustore
