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for aparallel plate capacitor, capacitance is inversely proportional to d, hence it will decrease.
the variation of potential depends on whether the capacitor is connected in a circuit or isolated.
If connected in a circuit, the potential remains constant(charge varies)
if isolated, charge remains constant, hence potentail increases.
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r is costt.
when v will be high, i will also be high???
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I can get this far
let x^(lny)=a
x^)lnz)=b
y^l(lnz)=c
then the given expression reduces to : a/b + a/c + b/c
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Why is electricity from power plants is transmitted at high potential difference???
Power is v*v/r, it will increase????
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y1=8sin(omega*t)
y2=6cos(omega*t)
y3=-4sin(omega*t)
y4=-2cos(omega*t)
y=y1+y2+y3+y4=4(sin(omega*t)+cos(omega*t))
hence
amplitude:4*square root of 2
phase:pi/4
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the rule is that if there is a diffference of 1.7, then the molecule possess 50% ionic character(for 100%, electronegativity difference-->infinity)
1.4 difference means that more covalent than ionic
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Just one small question:
It is said that light coming from fish's eye at an angle greater tan critical angle suffers TIR at the surface of water and hence fish has limited vision. Right.
But, a creature,s vision depends on the light entering. If light is entering from air, how can it suffer TIR??
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I know its soution :
Observe the hypotenuse of the original triangle.It seems straight, but it s not.
Calculate the slope of hypotenuse of green triangle and red triangle, they are different indicating that hypotenuse of the original triangle is not straight line.
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I don't know about the method, but the concept is given in our syllabus
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nikhil
I have something for you.
first notation, since I can't use usual notations due to inability
a: mass of electron
b:mass of proton
e:charge of proton
r:the required distance
v:initial velocity of electron
w:final velocity of proton
the question is one dimensional interaction between proton and electron. The system consists of electeon and proton, and they attract each other through conservative electric field(magnetic effects are neglected).
Applying law of consevation of momentum
av=a*2v-b*w
(if electron is moving initiallly in positive x-direction, then finally it will be moving in +x and proton in -x due to mutual attraction)
Aplplying law of conservation of energy
a*v*v/2=a*2v*2v/2+b*w*w/2-eV(r)
Using, these two equations, you can find r
if you find w from first equation and substitute in second equation, you observe that kinetic energy of proton involves square of a/b, which is very small and hence can be neglected.
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in the equation, I hope that the sides of triangle are joining the non-adjacent vertices of the triangle
three vertices of a triangle can be chosen in C(n,3) ways.
three vertices are chosen that they are three consecutive sides: n
three vertices chosen so that two of them are adjacent:(n-4)*C(n,1)
the required no. of ways=C(n,3)-n-(n-4)*C(n,1)
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can you just give me the equation of the tangents from the point(x,y) to the circle of radius r with centre at (0,0)
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here is how I got the range
let D be the mid-point of BC
let AM be the altitude of triangle
let 'd' be the distance between O(circumcentre) and H(orthocentre)
let 2a be the length of BC
consider triangle BDO, find DO in terms of a and A
DO=atanA.........................(1)
consider triangle BMH, find MH in terms of a,d and C
MH=(a-d)tanC.........................(2)
consider triangle CMH, find MH in terms of a,d and B
MH=(a-d)tanB.........................(3)
since OH is parallel to BC
DO=MH
equate 1 and 2 find a/d
equade 1 and 3 find a/d
equate a/d found in above two steps
we will get a equation in tanA, tanB and tanC
now you can find the range using the following :
A+B+C=pi
B not equal to C(scalene) hence tanB not equal to tanC
tanB and tanC, both are greater than zero(acute triangle)
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Although I have solved it myself, follow this link
star.tau.ac.il/QUIZ/05/hrsol.pdf
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heater has a high restance so that a large amount of electric power is dissipated as heat energy, which we use
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picture is not working in last post
he general equation of a wave is
Asin(omega*t-theta)
omega=2pi/T=2pi*c/lambda
theta=x/lambda
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the general equation of a wave is
Asin(![]() ![]() ![]() ![]() t-)
now concerntrate on the angle term
=2pi/T=2pi*c/lambda
=x/lambda
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there is a proof for 1=2
ln2 = 1 -1/2 + 1/3 - 1/4 +....
ln2= (1+1/3+1/5+..)-(1/2+1/4+1/6+..)
adding and subtractng the last term
ln2= (1+1/3+1/5+..)-(1/2+1/4+1/6+..)+(1/2+1/4+1/6+..)-(1/2+1/4+1/6+..)
ln2= (1+1/3+1/5+..)-(1/2+1/4+1/6+..)-(1/2+1/4+1/6+..)+(1/2+1/4+1/6+..)
ln2= (1+1/3+1/5+..)-2(1/2+1/4+1/6+..)+(1/2+1/4+1/6+..)
ln2=(1+1/2+1/3+1/4+..)-(1+1/2+1/3+1/4+..)
ln2=0
2=1
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yes, itmeans you imagine a graph or better draw a graph.
sippose the question is
sinx greater than or equal to 1/2
graph sinx
draw line y=1/2
you will see that if x is greater than pi/3 and less than 2pi/3 the condition is satisfied.
to generealise it, add 2npi
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this is a hint
Let PA touches C1 at M
then M is the mid-point of PA
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Vriti Edustore
