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q1. pls explain what is mesomer and diastereomers?
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the equation of the plane through the points (2,2,1) and (9,3,6) and perpendicular to the plane 2x+6y+6z-1=0 is a.3x+4y+5z=9 b.3x+4y-5z=9 c.3x+4y-5z-9=0 d.none
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the equation of the plane through the points (2,2,1) and (9,3,6) and perpendicular to the plane 2x+6y+6z-1=0 is a.3x+4y+5z=9 b.3x+4y-5z=9 c.3x+4y-5z-9=0 d.none
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q1. the distance from the pt. -i+2j+6k to the straight line through the point (2,3-4)and parallel the vector 6i+3j-4k. a.7 b.10 c.9 d.none of these pls reply fast goiitians ! rate assured....
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q3. how to identify that which of the following atom will not have alone pair of electron? a.N*ocl b.S*o2cl2 c.S*ocl2 d.S*o2
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q2.gold number of starch is 25.amount of starch that should be added to 100ml of gold solution in the presence of 1ml of 10% of nacl will be a. 250g b.0.025g c.0.25g d.none of these
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frd, the answer is 2 bcoz x+0+0-2=0 x=2
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q1.the maximum and the minimum ionic character from licl, rbcl, becl2, mgcl2. pls give the full explanation. q2.gold number of starch is 25.amount of starch that should be added to 100ml of gold solution in the presence of 1ml of 10% of nacl will be a. 250g b.0.025g c.0.25g d.none of these q3. how to identify that which of the following atom will not have alone pair of electron? a.N*ocl b.S*o2cl2 c.S*ocl2 d.S*o2
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the hybridisation of sncl2 is sp2
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explain the molecular orbital theory with example. also write the configuration of c,o2,o2+,o2-. . what is the difference in the configuration of carbon and oxygen?why? pls try to explain in short not in big paras!!!! thanx, waitin 4 reply............
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how dude, pls give full working!
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if a and b r the two independent events such thst p(a' intersection b)=2/15 and p(a intersection b')=1/6 then p(b') is a.1/5 b.1/6 c.4/5 d.5/6
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pls do this in both the way a.if repetition is allowedb.if repetition is not allowed
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using the digit 3,5,6,0 how many four digit no. can be formed and what is the sum of all the no.?
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what is the kjeldahl method? pls reply fast.............
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capacitor is device which is use to store charge. c=q/v s.i.unit farad
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for reflexive aRa or bRb should be there and for transitive the condition should be aRc , bRc then aRb
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if the points (0,0),(1,0),(0,1)and (t,t) r concyclic then t = a.-1 b.1 c.2 d.-2  is equal to
1.f(x)/g'(x) 2.f'(x)g(x) - f(x)g'(x) 3.f(x)g'(x) -. f'(x)g(x) 4.f'(x)g(x) + f(x)g'(x) pls do this goiitians !rating assured
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as we know, w/e=q/f i.e. gram equivalent is equal to the no of faraday ( from faraday 1,2 law) w=weight , e=equivalent weight q=charge, f= faraday using this formula we can find the equivqlent weight , 0.66/e=2*100/96500 , e=318.5 now we know that electrochemical equivalent (z) is given by e/f=318.5/96500=.0033 z=3.3*10-3
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work done is f.ds...............(1) force is i+j+k and the work is done from pt a (3,3,3) to b (4,4,4) from 1, ds represent the change in displacemant ,therefore ds=(4-3)i+(4-3)j+(4-3)k =i+j+k again from 1, w=f.ds (i+j+k)(i+j+k)=1+1+1=3
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Vriti Edustore
