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METHOD 2
x =1/2[# valence electrons + # monovalent + #of charges - #no charges
in the free central atom atoms on anion on cation
then compare with the following table
sp - 2
sp2 - 3
sp3-4
sp3d-5
sp3d2-6
sp3d3-7
ex- PCl 5 -----------
X= 1/2 [ 5 + 5 +0 + 0] = 5 it is sp3d
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METHOD 1
check my article for shortcut to hybridisation.........
link-----http://www.goiit.com/posts/list/community-shelf-shortcut-way-to-find-hybridisation-42596.htm
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instead u can pass all the sticks thru the midpoint
and toching the opposite points.........i dont know how to add a picture
C:\Documents and Settings\Administrator\My Documents\dots
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gud attempt....................close enuf anchit
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bro....i did the same mistake.........check out the mistake corrected by anand ............and u didn't do summation at all
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Two rods of equal length are lying one along x-axis and other along line y=x.
they intersect at origin at their midpoint . The first rod moves with velocity v1= vj
and the second with velocity v2 = v /  2 i - v / 2j . Find the velocity of point of intersection of two rods?
answer will be given later.................ok i'lll give it now itself...............
it is v ( 2.41i+j )
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tanx for the correction.............i'm not gud in algebra.................tanx guys
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sorry guys tanx for the correction
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i accept it....................but its test series is gud
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6. If the strings vibrates in 'p' loops. pth harmonic is produced then the frequency of pth harmonic is
fp = p / 2l ( T / m ) .
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is it v^2 = 2gr[ (cos@ - 1) / cos@ ]
i'm sure till here........................now let me guess
a = v^2/r
a = 2g [ (cos@ - 1 )/ cos@]
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ur sol. i went thru it....i don't understand why u did it
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ui think u hav misunderstood the question bro
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karthik bro check tat rajvarun problem fast
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