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First calculate poora mass.
Then calculate the mass at a distance of x/2.The tension that pulls it is such that its acceleration is same as that of the whole body.
Therefore get the tension
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tnx..no ill try myself first
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A+ib=i^i^i.....infinity
then A^2+b^2=?
is it e^-piB/2
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sry fr all the trubl...this is in the fiitjee module
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tried all this ...cant get it
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sry mistyped
mod(z-iw)=mod(z+iw)=2
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mod(z)<=1 and mod(w)<=1
mod(z+i)=mod(z-i)=2
Prove Im(z)=Re(w)
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Mass per unit length of the chain is M/L
When length x has reached the floor,then the chain has fallen thru a height x.
the speed of the last link falling on the floor is sqrt(2gx)
its final velocity becomes 0(as it comes to rest)
so force on it is dp/dt
=m/l*dx/dt*sqrt(2gx)
as dx/dt=sqrt(2gx)
force on the last link(falling,or just touching the floor) is 2gx * m/l
also the part lying on the table exerts x*m/l*g
therefore u can calculate total force
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if we ahve to calculate the velocity of the COM when the rod falls down,we use Conservation of energy.ow mg provides the torque to the rod.So is using COE correct?
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um..the hinge applies a force in both horizontal and vertical directions on the COM.Also the net force isnt along the rod...so y shud energy b conserved?
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How can energy be conserved in this case: a thin rod is hinged at its end and is vertical initially .it is pushed slightly and allowed to rotate about the horizontal axis through its end
there is a hinge force acting on it which is NOT along the rod(for instance when the rod makes an angle of 90 degress with the vertical,its angular acceleration is less than g therefore some upward force must be acting on it that isnt along the rod. Therefore it will do some work.) So how can we conserve energy?
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