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Match the following
z = cos x + i sin x
2 8 cos 3 x sin 5 x = a sin 8x + b sin 6x + c sin 4 x + d sin 2 x
then
Col 1 Col 2
A.) a = P.) -4
B.) b = Q.) 12
C.) c = R.) 2
D.) d = S.) -1
My confusion is that : Can we apply complex numbers here or have we got to do it using trigonometry only?
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You are correct sir answer must be wrong first answer is given a.It should be d. 
Thank you once again.
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Ok let me tell u d answer too
Its d.) e+1
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If b1 = 2 and bn = n( 1 + b n-1)  n  2 ,
then [n] [ ] b n+2 / (n+2)! = ?
a.) e b.) 2e
c.) e-1 d.) e+1
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Maybe answer is wrong then. lets wait for a few more answers.thanx for your efforts.Your answer maybe correct.
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I got the problem in a Narayana Rank Promoting Package.Answer given is D.
I dont know how. 
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Atleast according to me they are a little more than what has been said in the syllabus.
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Are these problems for IIT JEE or any other competitives? I guess not.
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In this way you will certainly come to the answer as only 4 of them are there.Now instead of providing the options give me your procedure along with the answer.
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No answer given is something else.Please try friends.Elastiboysai can u pls provide the graph?
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By the definition of critical points it says that the points where the derivative is 0 isnt it???So i am gettinng a different answer.But please try and help me out!
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The number of critical points for the function f(x) = 2 sin x [ cos x ] in the interval
x  [ - 2 , 2 ]
a.) 6 b.) 8
c.)10 d.) 12
Please explain your answer.
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There is no such criteria.....you have to cross a particular cut off marks irrespective of the marks you obtain in the individual subjects . Suppose you solve physics and chemistry all and correctly , get some 240 marks you will be all set to get an excellent rank even if you leave maths paper untouched ! But doing well in all the 3 sets the tune for a good rank.
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