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consider plane along incline as X-axis and the perpendicular plane to incline as Y-axis.

The working method is splitting the velocity into 2 components_ one along incline and other perpendicular to incline

Let V= root.(2gh)

IN X axis
Sx = VsinOT + .5 gsinO T^2
IN Y axis
T= 2 VcosO\gcosO= 2V\g
put T as 2V\g in first eq to get 4V^2 sinO\g = 8hsinO

If this explanation isnt sufficient do tell me

you can scan the diagram and save it in a file and upload it or draw it in paint by yourself and send it

Its Arnie cracker bcos he is aware that he is suspected on account of his dress

V x (R/r + sin $\alpha$ )

I didnt understand how the inclination of wedge $\alpha$ is oriented. I assumed the usual case of a wedge and block and got the ans as .329 g . Could you upload the diagram of this question if available? I would be glad to solve it.

Well I guess the question is framed wrongly.

It should read as

The maximum value of normal friction is called___limiting friction ______________