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 deepak_agarwal's messages in the community 1 2 3 ... 30 31 32 GO Go to Page...
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 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
i will just tell u how u can do...try and see...

first of all expand cos(a+b)=cosa cosb - sina sin b

now one of the terms cums in as 2cos^2a cos^2b..write it as cos^2a cos^2b + cos^2a cos^2b...now combine this wid each one of the terms cos^2a...try it its easy
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
aint there any constraints on  value of a...and are u sure ans in root of 2
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
niki has dun a wondeful job....please use the equation editor to write the ques clearly so dat efforts of ppl like sre dont go waste...have a nice tym..!!
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
feynmann has dun a "feynmann" like job..gud...!!!
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
yaar simply take 1st two terms and apply formula..similarly next two terms...go on...a sine term will cum out to be common..tht will help u..see nw
 Discussion Forums -> This Post 2 points    (0    in 1 votes )   [?]
now at first u chose 1st candy...u have 8 choices in the form of 8 brands...so u have 8 ways to select first candy..now when chosing 2nd candy u again have 8 choices as repetiton allowd...so in all u have 8 to the power 6 ways
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
lambda=5890 angstrom
l=0.10
d=0.50

simply use the formula (lambda)(l)/(d)....see u gotts understand this becoz this ques is sure in jee..and its so simple..just see its picture in book...its like u r sending a ligth of sum wavelength thru a slit so as to convert it to monochromatic light...it falls on a scree where image is formed...l is distnce of screen from the slit..and d is place on screen where we wish tomeasure
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
avdesh has given rite reasoning...
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
whts an ID curve??please write the full form
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
well tarin bansal is absolutely correctly...and Det means determinant....as u may have dun in matrices....
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
hello..well coaching is really not essential to succeed..blv me...and it is nt at all late..u have still abt one and half year left...self study is enf if it is directed..all i wud suggest is get correspondence course of any good coaching insti fitjee vidyamandir brilliant which ever is convenient to u..study those packages and ncert books thoroughly wid proper revision schedule(very imp)..and once in a month u can go out and give xam to see if u r goin rite...
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
hey pops...well i appreciate ur eagerness to noe new things but it is completely outa syllabus...i can tell u but i have studied here in college and it wud be tuf to xplain u ..so just be cool like ur name pops..hehe
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
hey hi..well yaar force is always in direction of acceleration or rather acceleration is in direction of force and as for work W=F.S..because of this dot product W has no direction ..it simply follows distance
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
normal incident rays mean when incoming rays hit at alost 0 angle with normal..this is said in ques because if u read the lenses carefully then in order to use the formula the assumption is tht the rays are very close and hit normally
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
see truly speakin these ques are nt in course and they never form part of whole ques...we can do one thing..just tell me any ques related to it and then we can do it and tht will be better for u
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
well mgmpcm i have never heard of tan A position of magnet..i hope u have written exact word and no shortcut..i tried searching on google as well...i dun think so it is in course
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
hello akkifort..well first of all i must tell u tht these type of ques are really important and u must learn their algorithm...

see first of all identify all the forces on the electron particle just like any mechanics problem...here there are two forces due to electric field(u noe tht voltage and charge of electron) and nother due to magnetic field(B)...now these two forces act in different directions..electric force along wid vel and magnetic force perpendicular to vel..so u noe the two accelration directions and magnitude...initial vel is zero and finally it will form a parabola by applyin distance time equation in x and y axis....i hope now u wud be able to do...goodluck
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
Huygens
The two element Huygens eyepiece was invented by Christiaan Huygens in the 17th century. This optical design is now considered obsolete. Their main use in optics is as an example of the simplest possible compound lens design.
Despite being deprecated, these eyepieces are inexpensive to make and so are often sold with the cheapest telescopes and microscopes. Huygens eyepieces suffer from short eye relief, high image distortion (especially on short focus telescopes), chromatic aberration and have very narrow apparent field of view.
Essentially their only good use is for projection of a solar image onto a screen. Because Huygens eyepieces do not contain cement to hold the lens elements, they are less likely to be damaged by the intense, concentrated light of sun. Lens cement can overheat and either dissolve or burn.
Huygens eyepieces consist of two plano-convex lenses with the plane sides towards the eye separated by an air gap. The lenses are called the eye lens and the field lens. It is usually designed for zero transverse chromatic aberration. The focal plane is located between the two lenses. If the lenses are made of glass of the same refractive index, to be used with a relaxed eye and a telescope with an infinitely distant objective then the separation is given by:
$d= \frac{1}{2} (f_A + f_B)$
where fA and fB are the focal lengths of the component lenses.
 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
l=a+(n-1)d
m=p+(n-1)q
Sn=n/2(a+l)
Tn=n/2(p+m)

now Sn/Tn=2=(a+l)/(p+m)
(l-a)/(m-p)=d/q
=> dl/qm=(l/m)(l-a)/(m-p)
now simply use 1st eqn

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]
hey cumene..if u wud please rephrase the question..i amt able to understand the second line..i think theres sum typing error..please make sure u r writing the exact ques and nt in any case in ur own words
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