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learn up referring dc pandey,
constratint relations
referring hcv,
learn how to keep tension as a variable, fix the sense of direction & finally solve the equations...
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let d be the common difference... 14 + 3d = 3 so, d = -11/3 (common difference is -ve) a = 14 + d b = 14 + 2d so, a = 10.33 b = 6.67 im quite sure i think of these answers... i think the answers u gave r wrong
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4th term = a+3d & 7th term = a+6d so (a+3d) = 3a & a+6d = 2*(a+2d) + 1 => 3d = 2a => 3d/2 + 6d = 3d + 4d + 1 => 3d/2 - d = 1 => d = 2 so, 2a = 3*2 => a = 3
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can anyone in the rank range 1250 to 1750 pls post ur marks? plzzz
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wherein you can lend, sell, buy, borrow books, CDs, mobiles, etc
the more the people join, the more useful the site becomes... & YOU COULD AVOID BUYING THOSE MANY COSTLY JEE BOOKS by just sharing them. PS: this site aims at REDUCING GLOBAL WARMING by mutual helping... visit the site and know more.......plsssssss join ALSO TELL ALL YOUR FRIENDS ABOUT THIS SITE... remember: THE MORE THE POEPLE JOIN THIS SITE AND ARE WILLING TO HELP, THE MORE you WILL BE BENIFITTED!!!! please DON'T rate tis article... if you really want to help, then join in www.socialway.com & actively participate in that site.
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i think u MUST join BITS, even if it is Goa campus, for an MSc course... an option of DUAL DEGREE in the 2nd yr is there no??
NIE Mysore???? it sux dude!!! to the core! even if it is CSE...
see, at least if u r joinin RV college, BMSCE, PESIT, MS Ramiah all of which are in Blore & that too for CSE / ECE, then & only then can u even CONSIDER leaving BITS Goa MSc!!!!
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maybeeeeeeeeee... just MAYBE, rebel has got a rank under 1000; so he is reluctant to tell this out coz after JEE he was hoping to be within AIR 10... this is just a hunch! no offense to ne1!!!!!!!!!!! i didnt qualify in JEE neway, but sayin this cuz rebel was sooooooooooo sure that he wud get 402 marx after JEE...
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ya correct... i think only rank holders of JEE have been given 1st preference. it was false that the xtended merit ppl would get 1st preference. im not in the counselling listof IIST... my IIT JEE appln no is: 6051181
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hey gau_dil, im sorry for not including IITR & IITG in my previous topic... no ill feelings about it da, dont get dissappointed and all... no harm intended of course IITR & IITG are way way above all the colls in india (except for maybe BITS pilani) but they are usually ranked below the other 5 IITs at positions within top 10... so i wanted to know, among the top 5, whats the order... thats all... and gau_dil, are u from IITR? pls do post if so! COMMON ppl the going is getting better... lets gather all the IITians on this site!
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is that all?? come on people, im sure you can do better than that.... im sure there are more than 4 IITians on this site! its just for fun, be sportive... :)
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just wanted to survey how many IITians are actually on this site apart from the experts... so let it begin. post ur: NAME WHICH YEAR U QUALIFIED IN JEE UR RANK IN JEE BRANCH U HAVE TAKEN & IN WHICH IIT this is just a FRIENDLY SURVEY... cmon IITians, be sporting and answer, no harm can be caused na!!! NOTE: ppl who passed JEE, but didnt take it for any reason, also pls post ur NAME, RANK and YEAR OF PASSING JEE...
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okay, this is what i think (i may be wrong - pls dont kill me for it)
so if a person is stationery, the CG of the man + bike system deos not coincide with the CM of the system, so torque due to gravity os produced and we fall...
but while moving, we balance, and the CG & CM (cemtre of mass) of the man + bike system is almost coinciding so negligibly small torque coupled with the momentum we have, we dont fall.
now, if while riding a bike you lean to one side (not just your head, your whole body) KEEPIN THE BIKE STRAIGHT, then a torque develops and we fall.... i think thats why while turning the bike we lean, in order to coincide the system's CG & CM so that we dont fall...
RATE if u r satisfied/ think i am correct...
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hey ya, the question is damn simple. a corresponds to 1, b to 2 (ie. occurs 2 times), c to 3 (ie. ocurs 3 times), etc. so, just sum up using summation of natural numbers: n(n+1)/2 = 288 so, on solving, u get approximately 23.5 as the +ve value of n... meaning that the 24th letter is the letter of the alphabet required... (reason why it is 24th letter & not 23rd: see, 1 means 'a' is appearing 1ce, 2 means 'b' is appearing 2ce..... 22 means the 22nd alphabet, that is 'v' is appearing 22 times, 23 means 'w' is appearing 23 times, 24 meany 'x' is appearing 24 times, but any fraction between 23 & 24 means that the letter corresponding to 24 has begun, but 24 of it [meaning 24 x's] has not been completed [so 23.5 means that 'w' is over 23 times & 'x' has begun its count, but only some 12 x's are counted for sum to add upto 288].... hope u got it, if not read again) so, answer is 'x' RATE my efforts...
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