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Q) from the roof a building of 32m high water drops are falling at regular intervals .it is found that fifth drop begins to drop at the instant when the first drop touches the ground .at this interval find the distance between successive drops.the g=10m/s2 Sol) Time taken by first drop to fall on the ground = t so 32 = (1/2) g t2 or t = 8 /  10 s so if first drop falls at time = 0s 5th drop falls after = 8 /  10 s thus time interval between each successive fall of drops = 2 /  10 s HENCE WHEN THE FIRST DROP STRIKES THE GROUND THE DISTANCE TRAVELLED BY OTHER DROPS WILL BE distance travelled by 2nd drop will be travelled in 6 /  10 s = (1/2) 10 (6 /  10) 2 = 18m Similarly, distance travelled by 3rd drop will be travelled in 4 /  10 s = 8m And distance travelled by 4th drop will be travelled in 2 /  10 s = 2m thus the distance between 1st and 2nd = 32 -18 = 14m 2nd and 3rd is = 18 - 8 = 10m 3rd and 4th is = 8 - 2 = 6m 4th and 5th is = 2 - 0 = 2m
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