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rakesh61 (1898)

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A 20 kg block is initially at rest a 75 N force is required to set block in motion . after the motion a force of 60N is applied to keep the block moving at constant speed the coefficient of static friction is
 
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elessar_iitkgp (2326)

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Static friction acts till the body doesn't move. Hence to overcome the static friction 75 N force is needed.
N = F1
static = F1/N = 75 N/ (20 kg)(9.8 m/s2) = 0.37



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iitkgp_bipin (6144)

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To overcome static friction 75 N is applied.

Hence, f = staticN

Here N = mg and f = 75 N

75 = static(20)(9.8)

static = 0.37



Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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