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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jan 2007 17:38:32 IST
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Find the values of parameter r so that the biquadratic x4- 4x3 - 8x2 + r = 0 has (i) no real roots (ii) all roots real and distinct (iii) exactly 2 real roots
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you have to run faster and faster so as to remain where you are.. even if you are on the right track you will get run over if you just keep sitting there...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jan 2007 19:22:49 IST
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x4--4x3-8x2+r=0 (i) suppose the roots to be (a+ib),(a-ib),(c+id)&(c-id)because complex roots occur in pair if the coefficients are rational. Now use the relations between roots & coefficients & compare the relations I hope you will get the answer. In the same way attempt the remaining parts of the ques. I have not solved the ques. yet. As soon as I solve it I'll give you the detailed sol.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jan 2007 20:20:55 IST
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Asmita I tried this method but no result is coming. Experts pl suggest some other way.
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you have to run faster and faster so as to remain where you are.. even if you are on the right track you will get run over if you just keep sitting there...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jan 2007 20:25:51 IST
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Aakriti are u sure because i am hoping u will arrive at some ans. try this if r=a^2+b^2+c^2 where a,b,c are real then r>=0 this thing has relevance in this ques. have u tried this?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jan 2007 22:26:43 IST
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if f(x) has n equal roots then f '(x) will have n-1 equal roots
you can use this condition
say,
if f(x) has no root then f ' (x) will also have no root
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The yardstick of human intelligence is the ability to overcome the last fallacy |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 11:50:48 IST
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Rahul please give your full solution.
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you have to run faster and faster so as to remain where you are.. even if you are on the right track you will get run over if you just keep sitting there...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 14:13:07 IST
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rahul_c i told u several times taht u r giving wrong answers y dunt u understand this, please do not give wrong answer untill and unless u understand the concept carefully , ur concepts are wrong , please see this example f(x) = (x-3)^2 + 4 this function has no solution but , f``(x) = 2(x-3) has real solution , i am telling u again , u only know answers , why & how terms are immaterial to u, figure it out , otherwise u know very will what will happen
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 14:27:42 IST
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and whosoever ask this question , please understand that this is not in the JEE syllabus ( biquadratic equation) , and if it will come then it will be some special case. If u wanna know solution of this question i can write that here , but nothin will be happened by that , it willl be very good for u if u give ur time to topics which are in syllabus Thnxs
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life is like red red rose |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 14:45:52 IST
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Listen , this is very much in the syllabus.. I am never free to do those things which are not in the course neither am I interested to do such things at this point of time . It came in my institute's test series . The discussion of the test will be on 17th and I am having my physics pre board on that day, so I thought of asking this to the experts. If you can provide any solution , I would be thankful.
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you have to run faster and faster so as to remain where you are.. even if you are on the right track you will get run over if you just keep sitting there...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 14:48:09 IST
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Do tell me if this can be solved using graphs.I've tried all other ways.
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you have to run faster and faster so as to remain where you are.. even if you are on the right track you will get run over if you just keep sitting there...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 14:53:15 IST
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well akriti , what i can say i also cleared JEE few years ago, i never requires this , even at that time paper was more tougher than now ............................neways this can be solved by converting it to standard form of biquadratic equation.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2007 15:45:38 IST
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hit_ur_hit whatever i have written is directly picked up from
HALL AND KNIGHT ALGEBRA
CHAPTER - THEORY OF EQUATIONS .CONTEXT NUMBER 557
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The yardstick of human intelligence is the ability to overcome the last fallacy |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Jan 2007 16:27:14 IST
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Hi Asmita, thanks for giving me so many salutes .. This is not to offend you or anything as such.. but I don't think I actually deserve all of them.. I mean you have even given me salutes on my own replies.
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you have to run faster and faster so as to remain where you are.. even if you are on the right track you will get run over if you just keep sitting there...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Jan 2007 17:05:51 IST
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i think what Rahul has said is correct . i looked into hall and knight it's there perhaps this sum can be solved by maxima minima condition and thereby drawing the graph .Although i myself haven't been able to do so. (No offence)mr hit_ur_heart should be polite to peple and respect others.if he has the solution he must post , without beating around the bush
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Jan 2007 17:18:01 IST
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