IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

angelh

^{LIM_x-->0= X sin(1/x) sin { 1/ X sin (1/x) }}

anchal_1991

is d ans 1.pls temme

rockery

Man. The answer is 0.

rini

the answer should be zero because x is multiplyed by some finite quantity..

kishan12

if the second bracket is a fractional part bracket, the answer is 0
otherwise its 1.

correct me if i am wrong.i can give you a explanation if you confirm the answer

angelh

d ans is 1 u wil b rated if u explain

joyfrancis

well the answer should be zero.

sin funtions would always have a FINITE value.

so sin1/x is something finite and sin(1/xsinx) is also something finite

.: sin(1/x) sin{1/x sin (1/x)} would also be something finite

so it is

0*finite=0

kishan12

see yaar you can use the simple formula of sin that sinx/x =1 if limit tends to 0.
multiply and dium and den by 1/x then for the other sin again multiply and div whatever is there in place of theta.
again the same formula works and you get 1/xsin(1/x).
do the same thing and you get one .

kishan12

plzzzz rate me
not rated even once yaar

joyfrancis

xsin1/x ... multiply divide by 1/x we get

sin{1/x}/1/x

But

_{[x ]}

_{[ 0]} sin{1/x}/1/x is not 1.

Similarly

sin(1/xsin{1/x})

=sin(1/sin{1/x}/1/x)

but

[x ]

[ 0] sin{1/x}/1/x is not 1.

_{.:[x ][ 0]} sin(1/sin{1/x}/1/x) is not 1

.: the ans cannot be 1

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