IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

umang

whats the differentiation of x raised to the power x , i.e. , x^x ???????

jatinpreet

Maybe it can be solved by letting the expression be equal to say , u,
and taking log.
I m not sure though.

magiclko

yes, it will be done with logarithm approach,

let u= x^x

or, log u= x log x

differentiating both sides,

(1/u) u' = 1 + log x

u' = x^x (1 + log x)

done.........

pavneet

let u=x^x

log(u)=xlogx

differentiating both sides

u' * (1/u)=1 + logx

u'=x^x(1+ logx)

umang

Thanks a lot !!!!!

gorakavipraveen

umang the same quesyion wa sposted by me at quizmine.com, refer it so that you can atleast get 7 ways of solving the same problem.